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Educational Codeforces Round 61 (Rated for Div. 2) E. Knapsack //揹包dp||爆搜?
時間 2021-01-11
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http://codeforces.com/contest/1132/problem/E 首先,求出(1-8)的LCM,將w分成若干個揹包。 令cnt[i]∗i = ki * LCM + qi 。qi的取值範圍就是(0-LCM-1) 求出所有的 ∑qi 的情況下,使得 ∑ki 最大。 定義dp[i][j] 到第i個數,揹包累計放入j容量時,∑ki的數量。 dp[i][j]=max(dp[i][j]
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