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Educational Codeforces Round 61 (Rated for Div. 2)(題解)
時間 2020-03-13
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Educational Codeforces Round 61 (Rated for Div. 2)(題解) A. Regular Bracket Sequence 題目大意 給出一些括號串"((","()",")(","))" ,cnt1,cnt2,cnt3,cnt4個,問用這些括號串可否組成括號之間相互匹配的大括號串html 解題思路 只要「((」,"))「的數目相等,且在其都爲0時不存在」)
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相關文章
1.
Educational Codeforces Round 61 (Rated for Div. 2) E. Knapsack
2.
Educational Codeforces Round 47 (Rated for Div. 2) 題解
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Educational Codeforces Round 91 (Rated for Div. 2)題解
5.
Educational Codeforces Round 90 (Rated for Div. 2)題解
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【A題】Educational Codeforces Round 83 (Rated for Div. 2)
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Educational Codeforces Round 67 (Rated for Div. 2)
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Educational Codeforces Round 77 (Rated for Div. 2)
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