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Educational Codeforces Round 61 (Rated for Div. 2)(題解)
時間 2020-03-13
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Educational Codeforces Round 61 (Rated for Div. 2)(題解) A. Regular Bracket Sequence 題目大意 給出一些括號串"((","()",")(","))" ,cnt1,cnt2,cnt3,cnt4個,問用這些括號串可否組成括號之間相互匹配的大括號串html 解題思路 只要「((」,"))「的數目相等,且在其都爲0時不存在」)
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相關文章
1.
Educational Codeforces Round 61 (Rated for Div. 2) E. Knapsack
2.
Educational Codeforces Round 47 (Rated for Div. 2) 題解
3.
Educational Codeforces Round 92 (Rated for Div. 2)題解
4.
Educational Codeforces Round 91 (Rated for Div. 2)題解
5.
Educational Codeforces Round 90 (Rated for Div. 2)題解
6.
【A題】Educational Codeforces Round 83 (Rated for Div. 2)
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Educational Codeforces Round 67 (Rated for Div. 2)
8.
Educational Codeforces Round 77 (Rated for Div. 2)
9.
Educational Codeforces Round 86 (Rated for Div. 2) A~D
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Educational Codeforces Round 86 [Rated for Div. 2] Solution
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