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Educational Codeforces Round 67 (Rated for Div. 2) E. Tree Painting(樹形dp)
時間 2020-03-13
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題目連接 題意:要你求以每一個點爲根時,全部子樹和的最大值。 思路:能夠先dfs第一遍求出1爲根時的答案,那麼dp【v】=dp【u】+n-2*size【v】,(u是當前節點,v是u的兒子節點,size【v】是v的子樹大小)c++ #include<bits/stdc++.h> using namespace std; const int maxn=2e5+1; typedef long long
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相關文章
1.
Educational Codeforces Round 67 (Rated for Div. 2)
2.
Educational Codeforces Round 95 (Rated for Div. 2) [A -- E]
3.
Educational Codeforces Round 61 (Rated for Div. 2) E. Knapsack
4.
Educational Codeforces Round 61 (Rated for Div. 2)(題解)
5.
Educational Codeforces Round 74 (Rated for Div. 2)
6.
Educational Codeforces Round 62 (Rated for Div. 2)
7.
Educational Codeforces Round 54 (Rated for Div. 2): E. Vasya and a Tree(DFS+差分)
8.
Educational Codeforces Round 69 (Rated for Div. 2)
9.
Educational Codeforces Round 107 (Rated for Div. 2)
10.
Educational Codeforces Round 57 (Rated for Div. 2)
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