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Educational Codeforces Round 67 (Rated for Div. 2) E. Tree Painting(樹形dp)
時間 2020-03-13
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題目連接 題意:要你求以每一個點爲根時,全部子樹和的最大值。 思路:能夠先dfs第一遍求出1爲根時的答案,那麼dp【v】=dp【u】+n-2*size【v】,(u是當前節點,v是u的兒子節點,size【v】是v的子樹大小)c++ #include<bits/stdc++.h> using namespace std; const int maxn=2e5+1; typedef long long
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相關文章
1.
Educational Codeforces Round 67 (Rated for Div. 2)
2.
Educational Codeforces Round 95 (Rated for Div. 2) [A -- E]
3.
Educational Codeforces Round 61 (Rated for Div. 2) E. Knapsack
4.
Educational Codeforces Round 61 (Rated for Div. 2)(題解)
5.
Educational Codeforces Round 74 (Rated for Div. 2)
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Educational Codeforces Round 62 (Rated for Div. 2)
7.
Educational Codeforces Round 54 (Rated for Div. 2): E. Vasya and a Tree(DFS+差分)
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