第十一週總結java
1、知識總結編程
1.Collection和Map是Java集合框架的根接口。數組
2.List接口和Set接口繼承自Collection接口。
3.Set無序不容許元素重複。安全
HashSet (無序)
TreeSet (有序)
4.List有序且容許元素重複。框架
ArrayList
LinkedList
Vector
5.Map也屬於集合系統,但和Collection接口不要緊。Map是key對value的映射集合,其中key列就是一個集合。key不能重複,可是value能夠重複。dom
HashMap (無序)
TreeMap (有序)
WeakHashMap
Hashtable (無序,線程安全)
6.SortedSet和SortedMap接口對元素按指定規則排序,SortedMap是對key列進行排序。ide
7.ArrayList和Vector區別函數
ArrayList和Vector都實現了List接口,都是經過數組實現的。
ArrayList是非線程安全的, Vector是線程安全的。
List第一次建立的時候,會有一個初始大小,隨着不斷向List中增長元素,當List 認爲容量不夠的時候就會進行擴容。ArrayList增加原來的50%,Vector缺省狀況下自動增加原來一倍的數組長度。
8.ArrayList和LinkedList區別及使用場景oop
區別:學習
ArrayList底層是用數組實現的,能夠認爲ArrayList是一個可改變大小的數組, 查找速度快。隨着愈來愈多的元素被添加到ArrayList中,其大小是動態增長的。
LinkedList底層是經過雙向鏈表實現的, LinkedList和ArrayList相比,增刪的速度較快。可是查詢和修改值的速度較慢。同時,LinkedList還實現了Queue接口,因此他還提供了offer(),peek(), poll()等方法。
使用場景:
ArrayList更適合快速檢索、以及在末尾插入或刪除(數組的特性)。
LinkedList更適合從中間插入或者刪除(鏈表的特性)。
2、實驗
1、實驗目的與要求
(1) 掌握Vetor、Stack、Hashtable三個類的用途及經常使用API;
(2) 瞭解java集合框架體系組成;
(3) 掌握ArrayList、LinkList兩個類的用途及經常使用API。
(4) 瞭解HashSet類、TreeSet類的用途及經常使用API。
(5)瞭解HashMap、TreeMap兩個類的用途及經常使用API;
(6) 結對編程(Pair programming)練習,體驗程序開發中的兩人合做。
2、實驗內容和步驟
實驗1: 導入第9章示例程序,測試程序並進行代碼註釋。
測試程序1:
l 使用JDK命令運行編輯、運行如下三個示例程序,結合運行結果理解程序;
l 掌握Vetor、Stack、Hashtable三個類的用途及經常使用API。
import java.util.Vector; class Cat { private int catNumber; Cat(int i) { catNumber = i; } void print() { System.out.println("Cat #" + catNumber); } } class Dog { private int dogNumber; Dog(int i) { dogNumber = i; } void print() { System.out.println("Dog #" + dogNumber); } } public class CatsAndDogs { public static void main(String[] args) { Vector cats = new Vector(); for (int i = 0; i < 7; i++) cats.addElement(new Cat(i)); cats.addElement(new Dog(7)); for (int i = 0; i < cats.size(); i++) ((Cat) cats.elementAt(i)).print();//進行強制類型轉化 } }
示例一結果:
由結果知道示例一代碼不合適,改後爲:
import java.util.Vector;//實現自動增加的對象數組 class Cat { private int catNumber; Cat(int i) { catNumber = i; } void print() { System.out.println("Cat #" + catNumber); } } class Dog { private int dogNumber; Dog(int i) { dogNumber = i; } void print() { System.out.println("Dog #" + dogNumber); } } public class CatsAndDogs { public static void main(String[] args) { Vector cats = new Vector(); for (int i = 0; i < 7; i++) cats.addElement(new Cat(i)); cats.addElement(new Dog(7)); for (int i = 0; i < cats.size(); i++) if (cats.elementAt(i) instanceof Cat) //判斷是否能進行強制類型轉換 { ((Cat) cats.elementAt(i)).print();//能進行強制類型轉換,輸出爲Cat型 } else { ((Dog) cats.elementAt(i)).print();//不能進行強制類型轉化,輸出爲Dog型 } } }
改後結果爲:
import java.util.*; public class Stacks //定義棧 { static String[] months = { "1", "2", "3", "4" }; public static void main(String[] args) { Stack stk = new Stack(); for (int i = 0; i < months.length; i++) stk.push(months[i]);//進棧操做 System.out.println(stk); System.out.println("element 2=" + stk.elementAt(2)); while (!stk.empty()) System.out.println(stk.pop());//出棧操做,並輸出 } }
結果:
import java.util.*; class Counter { int i = 1;//i不加權限修飾符,因此i的缺省權限修飾符應該是friendly型 public String toString() //轉爲字符串類型的數據 { return Integer.toString(i); } } public class Statistics { public static void main(String[] args) { Hashtable ht = new Hashtable();//Hashtable保存集合數據,用鍵值對的方式保存集合數據 for (int i = 0; i < 10000; i++) { Integer r = new Integer((int) (Math.random() * 20));//生成0到19,即20個整型隨機數 if (ht.containsKey(r))//判斷r是不是哈希表中一個元素的鍵值 ((Counter) ht.get(r)).i++;//利用Counter類對象去引用屬性值 else ht.put(r, new Counter());//r是隨機數,新建立的Counter對象的初始值是1 } System.out.println(ht); } }
結果:
測試程序2:
l 使用JDK命令編輯運行ArrayListDemo和LinkedListDemo兩個程序,結合程序運行結果理解程序;
import java.util.*; public class ArrayListDemo//ArrayList使用了數組的實現 { public static void main(String[] argv) { ArrayList al = new ArrayList(); //在ArrayList中添加大量元素 al.add(new Integer(11)); al.add(new Integer(12)); al.add(new Integer(13)); al.add(new String("hello"));//下標從0開始,添加4個元素 // First print them out using a for loop. System.out.println("Retrieving by index:"); for (int i = 0; i < al.size(); i++) { System.out.println("Element " + i + " = " + al.get(i));//經過get方法找到 } } }
結果:
添加一個輸出一個集合對象的結果:
import java.util.*; public class LinkedListDemo { public static void main(String[] argv) { LinkedList l = new LinkedList(); l.add(new Object()); l.add("Hello"); l.add("zhangsan"); ListIterator li = l.listIterator(0); while (li.hasNext()) System.out.println(li.next()); if (l.indexOf("Hello") < 0) System.err.println("Lookup does not work"); else System.err.println("Lookup works"); } }
結果:
在Elipse環境下編輯運行調試教材360頁程序9-1,結合程序運行結果理解程序;
l 掌握ArrayList、LinkList兩個類的用途及經常使用API。
import java.util.*; /** * This program demonstrates operations on linked lists. * @version 1.11 2012-01-26 * @author Cay Horstmann */ public class LinkedListTest { public static void main(String[] args) { //建立a和b兩個鏈表 List<String> a = new LinkedList<>(); a.add("Amy"); a.add("Carl"); a.add("Erica"); List<String> b = new LinkedList<>(); b.add("Bob"); b.add("Doug"); b.add("Frances"); b.add("Gloria"); //合併a和b中的詞 ListIterator<String> aIter = a.listIterator(); Iterator<String> bIter = b.iterator(); while (bIter.hasNext()) { if (aIter.hasNext()) aIter.next(); aIter.add(bIter.next()); } System.out.println(a); //從第二個鏈表中每隔一個元素刪除一個元素 bIter = b.iterator(); while (bIter.hasNext()) { bIter.next(); // skip one element if (bIter.hasNext()) { bIter.next(); // skip next element bIter.remove(); // remove that element } } System.out.println(b); // bulk operation: remove all words in b from a a.removeAll(b); System.out.println(a);//經過toString方法打印出鏈表a中的全部元素 } }
測試程序3:
l 運行SetDemo程序,結合運行結果理解程序;
import java.util.*; public class SetDemo { public static void main(String[] argv) { HashSet h = new HashSet(); //也能夠 用Set h=new HashSet(); h.add("One"); h.add("Two"); h.add("One"); // 複製 h.add("Three"); Iterator it = h.iterator(); while (it.hasNext()) { System.out.println(it.next()); } } }
結果:
|在Elipse環境下調試教材365頁程序9-2,結合運行結果理解程序;瞭解HashSet類的用途及經常使用API。
l 在Elipse環境下調試教材367頁-368程序9-三、9-4,結合程序運行結果理解程序;瞭解TreeSet類的用途及經常使用API。
import java.util.*; /** * This program uses a set to print all unique words in System.in. * @version 1.12 2015-06-21 * @author Cay Horstmann */ public class SetTest { public static void main(String[] args) { Set<String> words = new HashSet<>(); // HashSet implements Set long totalTime = 0; try (Scanner in = new Scanner(System.in)) { while (in.hasNext()) { String word = in.next(); long callTime = System.currentTimeMillis(); words.add(word); callTime = System.currentTimeMillis() - callTime; totalTime += callTime; } } Iterator<String> iter = words.iterator(); for (int i = 1; i <= 20 && iter.hasNext(); i++) System.out.println(iter.next()); System.out.println(". . ."); System.out.println(words.size() + " distinct words. " + totalTime + " milliseconds."); } }
import java.util.*; /** * An item with a description and a part number. */ public class Item implements Comparable<Item>//接口 { private String description; private int partNumber; /** * Constructs an item. * * @param aDescription * the item's description * @param aPartNumber * the item's part number */ public Item(String aDescription, int aPartNumber)//構造器 { description = aDescription; partNumber = aPartNumber; } /** * Gets the description of this item. * * @return the description */ public String getDescription() { return description; } public String toString() { return "[description=" + description + ", partNumber=" + partNumber + "]"; } public boolean equals(Object otherObject) { if (this == otherObject) return true; if (otherObject == null) return false; if (getClass() != otherObject.getClass()) return false; Item other = (Item) otherObject; return Objects.equals(description, other.description) && partNumber == other.partNumber; } public int hashCode() { return Objects.hash(description, partNumber); } public int compareTo(Item other)//排序 { int diff = Integer.compare(partNumber, other.partNumber); return diff != 0 ? diff : description.compareTo(other.description); } }
package treeSet; import java.util.*; /** * An item with a description and a part number. */ public class Item implements Comparable<Item> { private String description; private int partNumber; /** * Constructs an item. * * @param aDescription * the item's description * @param aPartNumber * the item's part number */ public Item(String aDescription, int aPartNumber) { description = aDescription; partNumber = aPartNumber; } /** * Gets the description of this item. * * @return the description */ public String getDescription() { return description; } public String toString() { return "[description=" + description + ", partNumber=" + partNumber + "]"; } public boolean equals(Object otherObject) { if (this == otherObject) return true; if (otherObject == null) return false; if (getClass() != otherObject.getClass()) return false; Item other = (Item) otherObject; return Objects.equals(description, other.description) && partNumber == other.partNumber; } public int hashCode() { return Objects.hash(description, partNumber); } public int compareTo(Item other) { int diff = Integer.compare(partNumber, other.partNumber); return diff != 0 ? diff : description.compareTo(other.description); } }
結果:
測試程序4:
l 使用JDK命令運行HashMapDemo程序,結合程序運行結果理解程序;
import java.util.*; public class HashMapDemo //基於哈希表的 Map接口的實現,提供全部可選的映射操做 { public static void main(String[] argv) { HashMap h = new HashMap(); // 哈希映射從公司名稱到地址 h.put("Adobe", "Mountain View, CA"); h.put("IBM", "White Plains, NY"); h.put("Sun", "Mountain View, CA"); String queryString = "Adobe"; String resultString = (String)h.get(queryString); System.out.println("They are located in: " + resultString); } }
結果:
l 瞭解HashMap、TreeMap兩個類的用途及經常使用API。l 在Elipse環境下調試教材373頁程序9-6,結合程序運行結果理解程序;
import java.util.*; /** * This program demonstrates the use of a map with key type String and value type Employee. * @version 1.12 2015-06-21 * @author Cay Horstmann */ public class MapTest { public static void main(String[] args) { Map<String, Employee> staff = new HashMap<>(); staff.put("144-25-5464", new Employee("Amy Lee")); staff.put("567-24-2546", new Employee("Harry Hacker")); staff.put("157-62-7935", new Employee("Gary Cooper")); staff.put("456-62-5527", new Employee("Francesca Cruz")); // print all entries System.out.println(staff); // remove an entry staff.remove("567-24-2546"); // replace an entry staff.put("456-62-5527", new Employee("Francesca Miller")); // look up a value System.out.println(staff.get("157-62-7935")); // iterate through all entries staff.forEach((k, v) -> System.out.println("key=" + k + ", value=" + v)); } }
結果:
實驗2:結對編程練習:
l 關於結對編程:如下圖片是一個結對編程場景:兩位學習夥伴坐在一塊兒,面對着同一臺顯示器,使用着同一鍵盤,同一個鼠標,他們一塊兒思考問題,一塊兒分析問題,一塊兒編寫程序。
如下實驗,就讓咱們來體驗一下結對編程的魅力。
l 肯定本次實驗結對編程合做夥伴:達拉草
l 各自運行合做夥伴實驗九編程練習1,結合使用體驗對所運行程序提出完善建議;
import java.io.BufferedReader; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.Scanner; public class Moom{ private static ArrayList<Mest> studentlist; public static void main(String[] args) { studentlist = new ArrayList<>(); Scanner scanner = new Scanner(System.in); File file = new File("D:\\身份證號.txt"); try { FileInputStream fis = new FileInputStream(file); BufferedReader in = new BufferedReader(new InputStreamReader(fis)); String temp = null; while ((temp = in.readLine()) != null) { Scanner linescanner = new Scanner(temp); linescanner.useDelimiter(" "); String name = linescanner.next(); String number = linescanner.next(); String sex = linescanner.next(); String age = linescanner.next(); String province =linescanner.nextLine(); Mest student = new Mest(); student.setName(name); student.setnumber(number); student.setsex(sex); int a = Integer.parseInt(age); student.setage(a); student.setprovince(province); studentlist.add(student); } } catch (FileNotFoundException e) { System.out.println("學生信息文件找不到"); e.printStackTrace(); } catch (IOException e) { System.out.println("學生信息文件讀取錯誤"); e.printStackTrace(); } boolean isTrue = true; while (isTrue) { System.out.println("1:字典排序"); System.out.println("2:輸出年齡最大和年齡最小的人"); System.out.println("3:尋找老鄉"); System.out.println("4:尋找年齡相近的人"); System.out.println("5:退出"); String m = scanner.next(); switch (m) { case "1": Collections.sort(studentlist); System.out.println(studentlist.toString()); break; case "2": int max=0,min=100; int j,k1 = 0,k2=0; for(int i=1;i<studentlist.size();i++) { j=studentlist.get(i).getage(); if(j>max) { max=j; k1=i; } if(j<min) { min=j; k2=i; } } System.out.println("年齡最大:"+studentlist.get(k1)); System.out.println("年齡最小:"+studentlist.get(k2)); break; case "3": System.out.println("家庭住址:"); String find = scanner.next(); String place=find.substring(0,3); for (int i = 0; i <studentlist.size(); i++) { if(studentlist.get(i).getprovince().substring(1,4).equals(place)) System.out.println("province"+studentlist.get(i)); } break; case "4": System.out.println("年齡:"); int yourage = scanner.nextInt(); int near=agematched(yourage); int value=yourage-studentlist.get(near).getage(); System.out.println(""+studentlist.get(near)); break; case "5": isTrue = false; System.out.println("退出程序!"); break; default: System.out.println("輸入錯誤"); } } } public static int agematched(int age) { int j=0,min=53,value=0,k=0; for (int i = 0; i < studentlist.size(); i++) { value=studentlist.get(i).getage()-age; if(value<0) value=-value; if (value<min) { min=value; k=i; } } return k; } }
public class Mest implements Comparable<Mest> { private String name; private String number ; private String sex ; private int age; private String province; public String getName() { return name; } public void setName(String name) { this.name = name; } public String getnumber() { return number; } public void setnumber(String number) { this.number = number; } public String getsex() { return sex ; } public void setsex(String sex ) { this.sex =sex ; } public int getage() { return age; } public void setage(int age) { this.age= age; } public String getprovince() { return province; } public void setprovince(String province) { this.province=province ; } public int compareTo(Mest o) { return this.name.compareTo(o.getName()); } public String toString() { return name+"\t"+sex+"\t"+age+"\t"+number+"\t"+province+"\n"; } }
結果:
她的這個程序思路清晰,每一個步驟都很完善,運行屢次結果都如上所示
l 各自運行合做夥伴實驗十編程練習2,結合使用體驗對所運行程序提出完善建議;
package MM; import java.util.Random; import java.util.Scanner; import java.io.FileNotFoundException; import java.io.PrintWriter; public class Demo{ public static void main(String[] args) { MNM counter=new MNM();//與其它類創建聯繫 PrintWriter out=null; try { out=new PrintWriter("D:/text.txt"); }catch(FileNotFoundException e) { e.printStackTrace(); } int sum=0; for(int i=0;i<10;i++) { int a=new Random().nextInt(100); int b=new Random().nextInt(100); Scanner in=new Scanner(System.in); //in.close(); switch((int)(Math.random()*4)) { case 0: System.out.println( ""+a+"+"+b+"="); int M = in.nextInt(); System.out.println(a+"+"+b+"="+M); if (M == counter.add(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break ; case 1: if(a<b) { int temp=a; a=b; b=temp; }//爲避免減數比被減數大的狀況 System.out.println(""+a+"-"+b+"="); /*while((a-b)<0) { b = (int) Math.round(Math.random() * 100); }*/ int N= in.nextInt(); System.out.println(a+"-"+b+"="+N); if (N == counter.reduce(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break ; case 2: System.out.println(""+a+"*"+b+"="); int c = in.nextInt(); System.out.println(a+"*"+b+"="+c); if (c == counter.multiply(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break; case 3: while(b==0) { b = (int) Math.round(Math.random() * 100);//知足分母不爲0 } while(a%b!=0) { a = (int) Math.round(Math.random() * 100); b = (int) Math.round(Math.random() * 100); } System.out.println(""+a+"/"+b+"="); while(b==0) { b = (int) Math.round(Math.random() * 100); } int c0= in.nextInt(); System.out.println(a+"/"+b+"="+c0); if (c0 == counter.devision(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break; } } System.out.println("totlescore:"+sum); System.out.println(sum); out.close(); } }
package MM; public class MNM <T>{ private T a; private T b; public void MNM() { a=null; b=null; } public MNM(T a,T b) { this.a=a; this.b=b; } public MNM() { // TODO 自動生成的構造函數存根 } public int add(int a,int b) { return a+b; } public int reduce(int a,int b) { if((a-b)>0) return a-b; else return 0; } public int multiply(int a,int b) { return a*b; } public int devision(int a,int b) { if(b!=0&&a%b==0) return a/b; else return 0; } }
結果:
在運行這個程序時,大概出了5道題以後不出來其餘題了,問題大概是我在輸入答案以前先按了回車鍵,在進行第二次操做時,一切正常
出錯狀況以下:
l 採用結對編程方式,與學習夥伴合做完成實驗九編程練習1;
import java.io.BufferedReader; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.Scanner; public class A{ private static ArrayList<Mest> studentlist; public static void main(String[] args) { studentlist = new ArrayList<>(); Scanner scanner = new Scanner(System.in); File file = new File("D:\\身份證號.txt"); try { FileInputStream fis = new FileInputStream(file); BufferedReader in = new BufferedReader(new InputStreamReader(fis)); String temp = null; while ((temp = in.readLine()) != null) { Scanner linescanner = new Scanner(temp); linescanner.useDelimiter(" "); String name = linescanner.next(); String number = linescanner.next(); String sex = linescanner.next(); String age = linescanner.next(); String province =linescanner.nextLine(); Mest student = new Mest(); student.setName(name); student.setnumber(number); student.setsex(sex); int a = Integer.parseInt(age); student.setage(a); student.setprovince(province); studentlist.add(student); } } catch (FileNotFoundException e) { System.out.println("學生信息文件找不到"); e.printStackTrace(); } catch (IOException e) { System.out.println("學生信息文件讀取錯誤"); e.printStackTrace(); } boolean isTrue = true; while (isTrue) { System.out.println("1:字典排序"); System.out.println("2:輸出年齡最大和年齡最小的人"); System.out.println("3:尋找老鄉"); System.out.println("4:尋找年齡相近的人"); System.out.println("5:退出"); String m = scanner.next(); switch (m) { case "1": Collections.sort(studentlist); System.out.println(studentlist.toString()); break; case "2": int max=0,min=100; int j,k1 = 0,k2=0; for(int i=1;i<studentlist.size();i++) { j=studentlist.get(i).getage(); if(j>max) { max=j; k1=i; } if(j<min) { min=j; k2=i; } } System.out.println("年齡最大:"+studentlist.get(k1)); System.out.println("年齡最小:"+studentlist.get(k2)); break; case "3": System.out.println("家庭住址:"); String find = scanner.next(); String place=find.substring(0,3); for (int i = 0; i <studentlist.size(); i++) { if(studentlist.get(i).getprovince().substring(1,4).equals(place)) System.out.println("province"+studentlist.get(i)); } break; case "4": System.out.println("年齡:"); int yourage = scanner.nextInt(); int near=agematched(yourage); int value=yourage-studentlist.get(near).getage(); System.out.println(""+studentlist.get(near)); break; case "5": isTrue = false; System.out.println("退出程序!"); break; default: System.out.println("輸入錯誤"); } } } public static int agematched(int age) { int j=0,min=53,value=0,k=0; for (int i = 0; i < studentlist.size(); i++) { value=studentlist.get(i).getage()-age; if(value<0) value=-value; if (value<min) { min=value; k=i; } } return k; } }
public class Mest implements Comparable<Mest> { private String name; private String number ; private String sex ; private int age; private String province; public String getName() { return name; } public void setName(String name) { this.name = name; } public String getnumber() { return number; } public void setnumber(String number) { this.number = number; } public String getsex() { return sex ; } public void setsex(String sex ) { this.sex =sex ; } public int getage() { return age; } public void setage(int age) { this.age= age; } public String getprovince() { return province; } public void setprovince(String province) { this.province=province ; } public int compareTo(Mest o) { return this.name.compareTo(o.getName()); } public String toString() { return name+"\t"+sex+"\t"+age+"\t"+number+"\t"+province+"\n"; } }
結果:
l 採用結對編程方式,與學習夥伴合做完成實驗十編程練習2。
import java.util.Random; import java.util.Scanner; import java.io.FileNotFoundException; import java.io.PrintWriter; public class Main{ public static void main(String[] args) { yunsuan counter=new yunsuan();//與其它類創建聯繫 PrintWriter out=null; try { out=new PrintWriter("D:/text.txt");//將文件裏的內容讀入到D盤名叫text的文件中 }catch(FileNotFoundException e) { System.out.println("文件找不到"); e.printStackTrace(); } int sum=0; for(int i=0;i<10;i++) { int a=new Random().nextInt(100); int b=new Random().nextInt(100); Scanner in=new Scanner(System.in); //in.close(); switch((int)(Math.random()*4)) { case 0: System.out.println( ""+a+"+"+b+"="); int c1 = in.nextInt(); out.println(a+"+"+b+"="+c1); if (c1 == counter.plus(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break ; case 1: if(a<b) { int temp=a; a=b; b=temp; }//爲避免減數比被減數大的狀況 System.out.println(""+a+"-"+b+"="); /*while((a-b)<0) { b = (int) Math.round(Math.random() * 100); }*/ int c2 = in.nextInt(); out.println(a+"-"+b+"="+c2); if (c2 == counter.minus(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break ; case 2: System.out.println(""+a+"*"+b+"="); int c = in.nextInt(); out.println(a+"*"+b+"="+c); if (c == counter.multiply(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break; case 3: while(b==0) { b = (int) Math.round(Math.random() * 100);//知足分母不爲0 } while(a%b!=0) { a = (int) Math.round(Math.random() * 100); b = (int) Math.round(Math.random() * 100); } System.out.println(""+a+"/"+b+"="); int c0= in.nextInt(); out.println(a+"/"+b+"="+c0); if (c0 == counter.divide(a, b)) { sum += 10; System.out.println("答案正確"); } else { System.out.println("答案錯誤"); } break; } } System.out.println("totlescore:"+sum); out.println(sum); out.close(); } }
public class yunsuan <T>{ private T a; private T b; public void yunsaun() { a=null; b=null; } public void yunsuan(T a,T b) { this.a=a; this.b=b; } public int plus(int a,int b) { return a+b; } public int minus(int a,int b) { return a-b; } public int multiply(int a,int b) { return a*b; } public int divide(int a,int b) { if(b!=0 && a%b==0) return a/b; else return 0; } }
結果:
按回車鍵依舊輸出10道題
3、實驗總結
在本次實驗中我學習到了一個新的方法:結對編程。這個方法可讓同窗們互相討論,共同進步,對於學習語言來講是一個很是好的方法;而且在學習語言中要積極去閱讀好的源碼,這樣更有利於本身的學習。