C++ operator 的一種不會的用法

自認爲對C++比較熟悉,忽然看到一些奇怪的代碼(在看網上下載的代碼Sockets):socket

class SocketAddress
{
public:
	virtual ~SocketAddress() {}

	/** Get a pointer to the address struct. */
	virtual operator struct sockaddr *() = 0;

	/** Get length of address struct. */
	virtual operator socklen_t() = 0;

	/** Compare two addresses. */
	virtual bool operator==(SocketAddress&) = 0;

	/** Set port number.
		\param port Port number in host byte order */
	virtual void SetPort(port_t port) = 0;

	/** Get port number.
		\return Port number in host byte order. */
	virtual port_t GetPort() = 0;

	/** Set socket address.
		\param sa Pointer to either 'struct sockaddr_in' or 'struct sockaddr_in6'. */
	virtual void SetAddress(struct sockaddr *sa) = 0;

	/** Convert address to text. */
	virtual std::string Convert(bool include_port) = 0;

	/** Reverse lookup of address. */
	virtual std::string Reverse() = 0;

	/** Get address family. */
	virtual int GetFamily() = 0;

	/** Address structure is valid. */
	virtual bool IsValid() = 0;

	/** Get a copy of this SocketAddress object. */
	virtual std::auto_ptr<SocketAddress> GetCopy() = 0;
};

奇怪的代碼:函數

/** Get a pointer to the address struct. */
	virtual operator struct sockaddr *() = 0;

	/** Get length of address struct. */
	virtual operator socklen_t() = 0;

最後搜了一下,才知道是對 類型轉換 的重載!this

socklen_t 是 int 類型 ;blog

聲明:operator XX(); 無返回值,XX就是某個類型;string

用法:XX a = (XX)obj; 假設上邊SocketAddress非abstract類,例如:SocketAddress sa; int a = (socklen_t)sa; 也就是此時會調用原成員函數operator XX(); 通常返回XX類型值,能夠理解成類型轉換的重載!it

另外:我竟不知道一個自定義類的 構造函數能夠用做隱形的類型轉換,例如:Class A { A(int i) { val = i};  private int val;} , A a = 5; 解:5 首先經過構造函數A(int)隱形的轉換爲A類型,而後調用默認的operator=賦值函數,賦值給a;class

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