案例01: 2008年8月8日20:08:08 日後88,888,888秒是哪天?星期幾?python
日期->時間戳(浮點數)->能夠作數學運算spa
演示:code
import time數學
# 構造日期的元組,元組必須是9位標準的it
tuple01 = (2008, 8, 8, 20, 8, 8, 0, 0, 0)import
# 把指定的日期轉換爲時間戳file
chinese_time = time.mktime(tuple01)程序
print(time.localtime(chinese_time))im
print(time.asctime(time.localtime(chinese_time)))時間戳
# 日後88888888秒
chinese_time += 88888888.0
# 輸出結果
print(time.localtime(chinese_time))
print("結果:", time.strftime("%Y-%m-%d %H:%M:%S",time.localtime(chinese_time)), end = "\t")
tule_weeb = ("星期一", "星期二", "星期三", "星期四", "星期五", "星期六", "星期日")
time.sleep(5) # 程序暫停5秒鐘
print(tule_weeb[time.localtime(chinese_time)[6]])
執行結果:
C:\python\python.exe C:/python/demo/file3.py
time.struct_time(tm_year=2008, tm_mon=8, tm_mday=8, tm_hour=20, tm_min=8, tm_sec=8, tm_wday=4, tm_yday=221, tm_isdst=0)
Fri Aug 8 20:08:08 2008
time.struct_time(tm_year=2011, tm_mon=6, tm_mday=3, tm_hour=15, tm_min=29, tm_sec=36, tm_wday=4, tm_yday=154, tm_isdst=0)
結果: 2011-06-03 15:29:36 星期五
Process finished with exit code 0
注意:程序暫停
Time.sleep() 程序暫停多少秒