轉載地址:http://blog.csdn.net/elsdnwn/article/details/45390771 java
package com.liujy.ui.wiget;import android.content.Context;import android.text.Editable;import android.text.Selection;import android.text.Spannable;import android.text.TextWatcher;import android.util.AttributeSet;import android.widget.EditText;public class ContainsEmojiEditText extends EditText { //輸入表情前的光標位置 private int cursorPos; //輸入表情前EditText中的文本 private String inputAfterText; //是否重置了EditText的內容 private boolean resetText; private Context mContext; public ContainsEmojiEditText(Context context) { super(context); this.mContext = context; initEditText(); } public ContainsEmojiEditText(Context context, AttributeSet attrs) { super(context, attrs); this.mContext = context; initEditText(); } public ContainsEmojiEditText(Context context, AttributeSet attrs, int defStyleAttr) { super(context, attrs, defStyleAttr); this.mContext = context; initEditText(); } // 初始化edittext 控件 private void initEditText() { addTextChangedListener(new TextWatcher() { @Override public void beforeTextChanged(CharSequence s, int start, int before, int count) { if (!resetText) { cursorPos = getSelectionEnd(); // 這裏用s.toString()而不直接用s是由於若是用s, // 那麼,inputAfterText和s在內存中指向的是同一個地址,s改變了, // inputAfterText也就改變了,那麼表情過濾就失敗了 inputAfterText= s.toString(); } } @Override public void onTextChanged(CharSequence s, int start, int before, int count) { if (!resetText) { if (count >= 2) {//表情符號的字符長度最小爲2 CharSequence input = s.subSequence(cursorPos, cursorPos + count); if (containsEmoji(input.toString())) { resetText = true; Toast.makeText(mContext, "不支持輸入Emoji表情符號", Toast.LENGTH_SHORT).show(); //是表情符號就將文本還原爲輸入表情符號以前的內容 setText(inputAfterText); CharSequence text = getText(); if (text instanceof Spannable) { Spannable spanText = (Spannable) text; Selection.setSelection(spanText, text.length()); } } } } else { resetText = false; } } @Override public void afterTextChanged(Editable editable) { } }); } /** * 檢測是否有emoji表情 * * @param source * @return */ public static boolean containsEmoji(String source) { int len = source.length(); for (int i = 0; i < len; i++) { char codePoint = source.charAt(i); if (!isEmojiCharacter(codePoint)) { //若是不能匹配,則該字符是Emoji表情 return true; } } return false; } /** * 判斷是不是Emoji * * @param codePoint 比較的單個字符 * @return */ private static boolean isEmojiCharacter(char codePoint) { return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA) || (codePoint == 0xD) || ((codePoint >= 0x20) && (codePoint <= 0xD7FF)) || ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) || ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF)); } }