iOS中日期和字符串的相互轉化

例一、 從服務器段獲取到的字符串轉化爲時間如:服務器

//網絡請求獲取的數據網絡

NSString *time = @"495946429";
    
    NSInteger num = [time integerValue];
    
    NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
    
    [formatter setDateStyle:NSDateFormatterMediumStyle];
    
    [formatter setTimeStyle:NSDateFormatterShortStyle];
    
    [formatter setDateFormat:@"YYYY-MM-dd"];
    
    NSDate *confromTimesp = [NSDate dateWithTimeIntervalSince1970:num];
    
    NSString *confromTimespStr = [formatter stringFromDate:confromTimesp];
    
    NSLog(@"%@",confromTimespStr);

轉化以後結果爲:1985-09-19code

 

例二、如何如何將一個字符串如「 20110826134106」裝化爲任意的日期時間格式,下面列舉兩種類型:orm

NSString *string = @"20110826134106";
    
    NSDateFormatter *inputFormatter= [[NSDateFormatter alloc] init];
    
    [inputFormatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en_US"]];
    
    [inputFormatter setDateFormat:@"yyyyMMddHHmmss"];
    
    NSDate *inputDate = [inputFormatter dateFromString:string];
    
    NSLog(@"date= %@", inputDate);
    
    
    
    NSDateFormatter *outputFormatter= [[NSDateFormatter alloc] init];
    
    [outputFormatter setLocale:[NSLocale currentLocale]];
    
    [outputFormatter setDateFormat:@"yyyy年MM月dd日 HH時mm分ss秒"];
    
    NSString *str= [outputFormatter stringFromDate:inputDate];
    
    NSLog(@"testDate:%@",str);

兩次打印的結果爲:字符串

date= 2011-08-26 05:41:06 +0000input

testDate:20110826 134106string

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