linux date 前一天等多種用法

時間 2020-09-12

標籤 linux date 前一天等多種用法欄目 Linux 简体版

原文原文鏈接

BASH SHELL中能夠定義變量顯示當前日期html

顯示當前日期是git

DATE=`date +%Y%m%d` +號後面是定義格式爲年月日ide

顯示前一天爲ui

DATE1=`date -d '1 days ago' +%Y%m%d` 加-d參數能夠設置與當前日期的計算時間，一樣，前2天爲'2 days ago'，去掉ago則爲當前日期以後多少天this

如下內容就是網上看到的一篇不錯的文章，出自http://www.labri.fr/perso/strandh/Teaching/USI/Common/Sh-utils/sh-utils_65.htmlidea

Here are a few examples. Also see the documentation for the `-d' option in the previous section.code

To print the date of the day before yesterday:
```
date --date='2 days ago'
```
To print the date of the day three months and one day hence:
```
date --date='3 months 1 day'
```
To print the day of year of Christmas in the current year:
```
date --date='25 Dec' +%j
```
To print the current full month name and the day of the month:
```
date '+%B %d'
```
But this may not be what you want because for the first nine days of the month, the `%d' expands to a zero-padded two-digit field, for example `date -d 1may '+%B %d'' will print `May 01'.
To print a date without the leading zero for one-digit days of the month, you can use the (GNU extension) - modifier to suppress the padding altogether.
```
date -d=1may '+%B %-d'
```
To print the current date and time in the format required by many non-GNU versions of date when setting the system clock:
```
date +%m%d%H%M%Y.%S
```
To set the system clock forward by two minutes:
```
date --set='+2 minutes'
```
To print the date in the format specified by RFC-822, use `date --rfc'. I just did and saw this:
```
Mon, 25 Mar 1996 23:34:17 -0600
```
To convert a date string to the number of seconds since the epoch (which is 1970-01-01 00:00:00 UTC), use the `--date' option with the `%s' format. That can be useful in sorting and/or graphing and/or comparing data by date. The following command outputs the number of the seconds since the epoch for the time one second later than the epoch, but in time zone five hours later (Cambridge, Massachusetts), thus a total of five hours and one second after the epoch:
```
date --date='1970-01-01 00:00:01 UTC +5 hours' +%s
18001
```
Suppose you had not specified time zone information in the example above. Then, date would have used your computer's idea of the time zone when interpreting the string. Here's what you would get if you were in Greenwich, England:
```
# local time zone used
date --date='1970-01-01 00:00:01' +%s
1
```
If you're sorting or graphing dated data, your raw date values may be represented as seconds since the epoch. But few people can look at the date `946684800' and casually note "Oh, that's the first second of the year 2000."
```
date --date='2000-01-01 UTC' +%s
946684800
```
To convert such an unwieldy number of seconds back to a more readable form, use a command like this:
```
date -d '1970-01-01 946684800 sec' +"%Y-%m-%d %T %z"
2000-01-01 00:00:00 +0000
```

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