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1092 To Buy or Not to Buy (20 point(s))
時間 2021-07-11
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#include<iostream> #include<cstdio> #include<string> using namespace std; const int MAXN = 256; int book[MAXN]; int miss; string s; int main() { cin >> s; for(int i = 0; i < s.length(); ++i) book[s[
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相關文章
1.
1092 To Buy or Not to Buy
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PAT 1092. To Buy or Not to Buy (20)
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PAT1092 To Buy or Not to Buy (20 分)
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