題目連接c++
題目大意 求每一個點對的lca深度的和spa
以每一層分析,得出通式code
因爲1e9的數據範圍要化簡表達式獲得O(能過)blog
瞎搞後就是2^(2n+2)-(4n+2)*2^n-2ci
code:get
#include<bits/stdc++.h> using namespace std; const long long mod = 1e9+7; long long n; long long ksm(long long aa,long long b) { long long ans=1; while(b) { if(b&1) ans=((ans%mod)*(aa%mod))%mod,ans%=mod; aa*=1LL*aa; aa%=mod; b>>=1; } return ans; } int main() { cin>>n; cout<<(ksm(2,2*n+2)-((4*n%mod+2)*ksm(2,n))%mod-2+mod)%mod;//處理負數加膜數取膜 return 0; }