servlet實時給前端發送數據_百度知道 - 360安全瀏覽器 8.1

servlet代碼以下
public void doPost(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {

		response.setContentType("text/html");
		PrintWriter out = response.getWriter();
		try {

			for (int i = 10; i <= 33; i++) {

				JSONArray jsonArray2 = JSONArray.fromObject(i*10);
				JSONArray jsonArray3 = JSONArray.fromObject((i));
				JSONObject jb = new JSONObject();
				jb.put("cpu", jsonArray2);
				jb.put("mem", jsonArray3);
				out.write(jb.toString());
				out.flush();
				Thread.sleep(3000);
			}
		} 
	}
JSP 用jquery接收數據代碼

                        setInterval(function() {                                   
                                    jQuery.getJSON('SomeServlet?cpu&mem', null,
                                    function(data) {
                                          var cpu = data.cpu;
                                        var mem = data.mem;
										
                                        for (var i=0;i<cpu.length;i++)

                                        {
                                       		 var x = (new Date()).getTime();
                                       	 	series_cpu.addPoint([x, parseInt(cpu[i])], true, true);
                                        	series_mem.addPoint([x, parseInt(mem[i])], true, true);
                                        }
                                    });
                                },
                                1000/*啓動間隔，單位ms*/
                                );
爲何在servlet加上一個for循環在前端就接收不到數據了呢？  不加for循環是程序是正常的。或者有其餘實現的辦法嗎？

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