Collections.addAll 爲何比collection.addall 快(轉)

from: http://stackoverflow.com/a/3343829/5032462html

在stackoverflow上看到的一篇回答,老外真是太professional了,mark一下。最後的summary值得看一下。java

 

The Java API docs say the following about Collections.addAllapi

The behavior of this convenience method is identical to that of c.addAll(Arrays.asList(elements)), but this method is likely to run significantly faster under most implementations.app

So if I understand correctly, a) is slower than b):less

a)ide

 Collection<Integer> col = new ArrayList<Integer>();
 col.addAll(Arrays.asList(1, 2, 3, 4, 5));

b)ui

Collection<Integer> col = new ArrayList<Integer>();
// Collections.addAll(col, Arrays.asList(1, 2, 3, 4, 5)); <-- won't compile
Collections.addAll(col, 1, 2, 3, 4, 5);

 

Let's take a closer look at the two of them:this

// a)
col.addAll(Arrays.asList(1, 2, 3, 4, 5));

Here's what happens:spa

  1. varags + autoboxing creates Integer[]
  2. Arrays.asList creates a List<Integer> backed by the array
  3. addAll iterates over a Collection<Integer> using Iterator<Integer>
// b)
Collections.addAll(col, 1, 2, 3, 4, 5);

Here's what happens:code

  1. varargs + autoboxing creates Integer[]
  2. addAll iterates over an array (instead of an Iterable<Integer>)

We can see now that b) may be faster because:

  • Arrays.asList call is skipped, i.e. no intermediary List is created.
  • Since the elements are given in an array (thanks to varargs mechanism), iterating over them may be faster than using Iterator.

That said, unless profiling shows otherwise, the difference isn't likely to be "significant". Do not optimize prematurely. While Java Collection Framework classes may be slower than arrays, they perform more than adequately for most applications.

 

API links

See also

Related questions


Summary

  • If you're adding elements from an array, you can use Collections.addAll(col, arr)
    • Remember that varargs are also done using arrays
  • If you're adding elements from a Collection, use col.addAll(otherCol)
    • Do NOT e.g. Collections.addAll(col, otherCol.toArray())
      • Such roundabout way is likely to be slower!
  • It's not that one is supremely faster than the other
    • It's about skipping unnecessary steps given the current situation
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