操做數組不要只會for循環

不少時候，咱們在操做數組的時候每每就是一個for循環幹到底，對數組提供的其它方法視而不見。看完本文，但願你能夠換種思路處理數組，而後能夠寫出更加漂亮、簡潔、函數式的代碼。

reduce

數組裏全部值的和

var sum = [0, 1, 2, 3].reduce(function (a, b) {
    return a + b;
}, 0);
// sum is 6

將二維數組轉化爲一維數組

var flattened = [[0, 1], [2, 3], [4, 5]].reduce(
    function (a, b) {
        return a.concat(b);
    },
    []
);
// flattened is [0, 1, 2, 3, 4, 5]

計算數組中每一個元素出現的次數

var names = ['Alice', 'Bob', 'Tiff', 'Bruce', 'Alice'];

var countedNames = names.reduce(function (allNames, name) {
    if (name in allNames) {
        allNames[name]++;
    }
    else {
        allNames[name] = 1;
    }
    return allNames;
}, {});
// countedNames is:
// { 'Alice': 2, 'Bob': 1, 'Tiff': 1, 'Bruce': 1 }

使用擴展運算符和initialValue綁定包含在對象數組中的數組

// friends - an array of objects 
// where object field "books" - list of favorite books 
var friends = [{
    name: 'Anna',
    books: ['Bible', 'Harry Potter'],
    age: 21
}, {
    name: 'Bob',
    books: ['War and peace', 'Romeo and Juliet'],
    age: 26
}, {
    name: 'Alice',
    books: ['The Lord of the Rings', 'The Shining'],
    age: 18
}];

// allbooks - list which will contain all friends' books +  
// additional list contained in initialValue
var allbooks = friends.reduce(function (prev, curr) {
    return [...prev, ...curr.books];
}, ['Alphabet']);

// allbooks = [
//   'Alphabet', 'Bible', 'Harry Potter', 'War and peace', 
//   'Romeo and Juliet', 'The Lord of the Rings',
//   'The Shining'
// ]

數組去重

var arr = [1, 2, 1, 2, 3, 5, 4, 5, 3, 4, 4, 4, 4];
var result = arr.sort().reduce(
    function (init, current) {
        if (init.length === 0 || init[init.length - 1] !== current) {
            init.push(current);
        }
        return init;
    },
    []
);
console.log(result); //[1,2,3,4,5]

數組變整數

var arr = [1, 3, 5, 7, 9];
arr.reduce(function (x, y) {
    return x * 10 + y;
}); // 13579

map

求數組中每一個元素的平方根

var numbers = [1, 4, 9];
var roots = numbers.map(Math.sqrt);
// roots的值爲[1, 2, 3], numbers的值仍爲[1, 4, 9]

格式化數組中的對象

var kvArray = [{key: 1, value: 10},
    {key: 2, value: 20},
    {key: 3, value: 30}];

var reformattedArray = kvArray.map(function (obj) {
    var rObj = {};
    rObj[obj.key] = obj.value;
    return rObj;
});

// reformattedArray 數組爲： [{1: 10}, {2: 20}, {3: 30}], 

// kvArray 數組未被修改: 
// [{key: 1, value: 10}, 
//  {key: 2, value: 20}, 
//  {key: 3, value: 30}]

用一個僅有一個參數的函數來mapping一個數字數組

var numbers = [1, 4, 9];
var doubles = numbers.map(function(num) {
  return num * 2;
});

// doubles數組的值爲： [2, 8, 18]
// numbers數組未被修改： [1, 4, 9]

反轉字符串

var str = '12345';
Array.prototype.map.call(str, function(x) {
  return x;
}).reverse().join('');

// 輸出: '54321'
// Bonus: use '===' to test if original string was a palindrome

every

檢測全部數組元素的大小

function isBigEnough(element, index, array) {
    return (element >= 10);
}

var passed = [12, 5, 8, 130, 44].every(isBigEnough);
// passed is false
passed = [12, 54, 18, 130, 44].every(isBigEnough);
// passed is true

filter

篩選排除掉全部的小值

function isBigEnough(element) {
  return element >= 10;
}
var filtered = [12, 5, 8, 130, 44].filter(isBigEnough);
// filtered is [12, 130, 44]

find

用對象的屬性查找數組裏的對象

var inventory = [
    {name: 'apples', quantity: 2},
    {name: 'bananas', quantity: 0},
    {name: 'cherries', quantity: 5}
];

function findCherries(fruit) {
    return fruit.name === 'cherries';
}

console.log(inventory.find(findCherries)); // { name: 'cherries', quantity: 5 }

尋找數組中的質數

function isPrime(element, index, array) {
  var start = 2;
  while (start <= Math.sqrt(element)) {
    if (element % start++ < 1) {
      return false;
    }
  }
  return element > 1;
}

console.log([4, 6, 8, 12].find(isPrime)); // undefined, not found
console.log([4, 5, 8, 12].find(isPrime)); // 5

some

測試數組元素的值

function isBigEnough(element, index, array) {
    return (element >= 10);
}

var passed = [2, 5, 8, 1, 4].some(isBigEnough);
// passed is false
passed = [12, 5, 8, 1, 4].some(isBigEnough);
// passed is true

sort

升序排序

var list = [1, 3, 7, 6];

list.sort(function(a, b) {
    return a-b;
});

降序排序

var list = [1, 3, 7, 6];

list.sort(function(a, b) {
    return b-a;
});

使用映射改善排序

// 須要被排序的數組
var list = ['Delta', 'alpha', 'CHARLIE', 'bravo'];

// 對須要排序的數字和位置的臨時存儲
var mapped = list.map(function (el, i) {
    return {index: i, value: el.toLowerCase()};
})

// 按照多個值排序數組
mapped.sort(function (a, b) {
    return +(a.value > b.value) || +(a.value === b.value) - 1;
});

// 根據索引獲得排序的結果
var result = mapped.map(function (el) {
    return list[el.index];
});