去掉重複的數字,返回list簡單代碼

package com.yanek.test;

import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.Set;

public class Test {

 /**
  * @param args
  */
 public static void main(String[] args) {

        //去掉重複的數字,返回list
  
  String ids="5;4;11;5;2;3;4;1;5;3";
  List idlist=getIdList1(ids,";");
  Collections.sort(idlist);
  System.out.println("idlist1:"+idlist);
  List idlist2=getIdList2(ids,";");
  Collections.sort(idlist2);
  System.out.println("idlist2:"+idlist2);

 }
 
 
 /**
  * 獲取ID列表
  * @param param
  * @param regex
  * @return
  * @throws Exception
  */
 public static List getIdList1(String param, String regex) {
  
  if (param == null || regex == null)
   return null;
  
  Set idSet = null;
  
  String[] ids = param.split(regex);
  if (ids != null) {
   for (int i = 0; i < ids.length; i++) {
    String id = ids[i];
    if (id != null && id.trim().length() > 0) {
     if (idSet == null) {
      idSet = new HashSet();
     }
     idSet.add(new Integer(id.trim()));
    }
   }
  }
  return idSet == null ? null : Collections.list(Collections.enumeration(idSet));
 }
 
 
 
 /**
  * 獲取ID列表
  * @param param
  * @param regex
  * @return
  * @throws Exception
  */
 public static List getIdList2(String param, String regex) {
  
  if (param == null || regex == null)
   return null;
  List list=new ArrayList();
  Map idmap=new HashMap();
  
  String[] ids = param.split(regex);
  if (ids != null) {
   for (int i = 0; i < ids.length; i++) {
    String id = ids[i];
    if (id != null && id.trim().length() > 0) {
     
                    if (!idmap.containsKey(id))
                    {
         list.add(new Integer(id.trim()));
         idmap.put(id,new Integer(id.trim()));
                    }
                    else
                    {
                     continue;
                    }
    }
   }
  }
  return list;
 }

}