oracle 去掉重複的數據

原理

根據id，count（id），查出須要去重id，去掉id，

具體能夠爲

select * from 表名 where id not in （select id ，count（id） from 表名 group by id having count（id）>1）

固然表名也能夠爲結果集

select  *  from (
with t AS (
SELECT id,pqmc,to_char(pqdd) AS aa from uf_pqjzb WHERE pqdd IS NOT NULL --AND ID ='57' 
)
select id,pqmc,regexp_substr(aa, '[^,]+', 1, level) as pqdd
 
from t 
 
connect by level <= regexp_count(aa, '\,\') + 1
 
and aa = prior aa
 
and prior dbms_random.value > 0

)  a where a.pqdd NOT in (SELECT pqdd FROM (
with t AS (
SELECT id,pqmc,to_char(pqdd) AS aa from uf_pqjzb WHERE pqdd IS NOT NULL --AND ID ='57' 
)
select id,pqmc,regexp_substr(aa, '[^,]+', 1, level) as pqdd
 
from t 
 
connect by level <= regexp_count(aa, '\,\') + 1
 
and aa = prior aa
 
and prior dbms_random.value > 0)  GROUP BY pqdd HAVING COUNT(pqdd)>1)