**前言:**在MySQL中 CONCAT ()函數用於將多個字符串鏈接成一個字符串,利用此函數咱們能夠將原來一步沒法獲得的sql拼接出來,在工做中也許會方便不少,下面主要介紹下幾個經常使用的場景。mysql
*注:*適用於5.7版本 低版本可能稍許不一樣。sql
SELECT DISTINCT
CONCAT(
'User: \'',
USER,
'\'@\'',
HOST,
'\';'
) AS QUERY
FROM
mysql.USER;
# 當拼接字符串中出現'時 需使用\轉義符
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SELECT
CONCAT(
'DROP table ',
TABLE_NAME,
';'
)
FROM
information_schema. TABLES
WHERE
TABLE_SCHEMA = 'test';
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SELECT
concat('KILL ', id, ';')
FROM
information_schema. PROCESSLIST
WHERE
STATE LIKE 'Creating sort index';
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SELECT
CONCAT(
'create database ',
'`',
SCHEMA_NAME,
'`',
' DEFAULT CHARACTER SET ',
DEFAULT_CHARACTER_SET_NAME,
';'
) AS CreateDatabaseQuery
FROM
information_schema.SCHEMATA
WHERE
SCHEMA_NAME NOT IN (
'information_schema',
'performance_schema',
'mysql',
'sys'
);
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SELECT
CONCAT(
'create user \'',
user,
'\'@\'',
Host,
'\''
' IDENTIFIED BY PASSWORD \'',
authentication_string,
'\';'
) AS CreateUserQuery
FROM
mysql.`user`
WHERE
`User` NOT IN (
'root',
'mysql.session',
'mysql.sys'
);
#有密碼字符串哦 在其餘實例執行 可直接建立出與本實例相同密碼的用戶
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#!/bin/bash
#Function export user privileges
pwd=yourpass
expgrants()
{
mysql -B -u'root' -p${pwd} -N $@ -e "SELECT CONCAT( 'SHOW GRANTS FOR ''', user, '''@''', host, ''';' ) AS query FROM mysql.user" | \
mysql -u'root' -p${pwd} $@ | \
sed 's/\(GRANT .*\)/\1;/;s/^\(Grants for .*\)/-- \1 /;/--/{x;p;x;}'
}
expgrants > /tmp/grants.sql
echo "flush privileges;" >> /tmp/grants.sql
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SELECT t.TABLE_SCHEMA,
t.TABLE_NAME,
t.TABLE_ROWS,
concat(round(t.DATA_LENGTH / 1024 / 1024, 2), 'M') AS size,
t.INDEX_LENGTH,
concat(round(t.DATA_FREE / 1024 / 1024, 2), 'M') AS datafree
FROM information_schema.tables t
WHERE t.TABLE_SCHEMA = 'test' order by DATA_LENGTH desc;
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#查找某一個庫無主鍵表
SELECT
table_schema,
table_name
FROM
information_schema.TABLES
WHERE
table_schema = 'test'
AND TABLE_NAME NOT IN (
SELECT
table_name
FROM
information_schema.table_constraints t
JOIN information_schema.key_column_usage k USING (
constraint_name,
table_schema,
table_name
)
WHERE
t.constraint_type = 'PRIMARY KEY'
AND t.table_schema = 'test'
);
#查找除系統庫外 無主鍵表
SELECT
t1.table_schema,
t1.table_name
FROM
information_schema. TABLES t1
LEFT OUTER JOIN information_schema.TABLE_CONSTRAINTS t2 ON t1.table_schema = t2.TABLE_SCHEMA
AND t1.table_name = t2.TABLE_NAME
AND t2.CONSTRAINT_NAME IN ('PRIMARY')
WHERE
t2.table_name IS NULL
AND t1.TABLE_SCHEMA NOT IN (
'information_schema',
'performance_schema',
'mysql',
'sys'
) ;
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歡迎你們收藏,其餘同窗有沒有相似實用的語句呢 也能夠分享出來哦!shell