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Educational Codeforces Round 89 (Rated for Div. 2) C - Palindromic Paths(迴文路徑,思惟)
時間 2020-08-04
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educational
codeforces
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palindromic
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迴文
路徑
思惟
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題目連接 題意 給你一個n*m的01矩陣,如今咱們要從起點(1,1)到(n,m)而且每一步只能向下或者向右走,如今要求他能走到終點的路徑必須所有是迴文(好比01010),問最少改動多少個元素,使得知足條件ios 思路: 例:矩陣爲 1.首先,要是路徑爲迴文,那麼我如今走的第一步,和最後走的一步確定要相等(廢話)。c++ 2.首先從起點咱們第一步能走到(1,2)和(2,1)這倆個座標,那麼他們走到的
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Educational Codeforces Round 89 (Rated for Div. 2)
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