Given the root
node of a binary search tree, return the sum of values of all nodes with a value in the range [low, high]
.java
Example 1:node
Input: root = [10,5,15,3,7,null,18], low = 7, high = 15 Output: 32
Example 2:3d
Input: root = [10,5,15,3,7,13,18,1,null,6], low = 6, high = 10 Output: 23
Constraints:code
[1, 2 * 10^4]
.1 <= Node.val <= 10^5
1 <= low <= high <= 10^5
Node.val
are unique.求樹中全部在指定範圍內的值得和。blog
DFS便可。it
class Solution { public int rangeSumBST(TreeNode root, int low, int high) { if (root == null) { return 0; } int sum = root.val >= low && root.val <= high ? root.val : 0; return sum + rangeSumBST(root.left, low, high) + rangeSumBST(root.right, low, high); } }