如何控制多線程執行順序

package com.thread;

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

/**
 * 如何控制多線程執行順序 
 * 一、join方法，讓主線程等待子線程執行完後再執行
 * 二、newSingleThreadExecutor,建立執行單個任務的線程池執行、保證全部任務按照指定順序(FIFO, LIFO, 優先級)執行
 */
public class ThreadFIFO {

    public static void main(String[] args) {
        thread1();
        thread2();
    }

    public static void thread2() {
        Thread thread1 = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println("thread1");

            }
        });
        Thread thread2 = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println("thread2");

            }
        });
        Thread thread3 = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println("thread3");

            }
        });
        ExecutorService executorService = Executors.newSingleThreadExecutor();
        executorService.submit(thread1);
        executorService.submit(thread2);
        executorService.submit(thread3);
        executorService.shutdown();
    }

    public static void thread1() {
        Thread thread1 = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println("thread1");

            }
        });
        Thread thread2 = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println("thread2");

            }
        });
        Thread thread3 = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println("thread3");

            }
        });
        try {
            // join 讓主線程等待子線程執行完後再執行
            thread1.start();
            thread1.join();
            thread2.start();
            thread2.join();
            thread3.start();
            thread3.join();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }
}