Codeforces Round #595 (Div. 3), problem: (A) Yet Another Dividing into Teams 【math + 貪心排序 +要麼1 要麼2】
Codeforces Round #595 (Div. 3), problem: (A) Yet Another Dividing into Teamsios 題目大意c++ n個學生 分別有不一樣的編程技能，而後編程技能之間差值等於1的兩個同窗不能處於同一團隊 問這些學生的最小團隊web 題解編程 mathsvg 排序，而後遍歷一遍，判斷是否存在兩個同窗的編程技能相差爲1，若是存在的話那就是兩個
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相關文章
- 1. Codeforces Round #595 (Div. 3)
- 2. Codeforces Round #598 (Div. 3)- E. Yet Another Division Into Teams - 動態規劃
- 3. Codeforces Round #598 (Div. 3) E. Yet Another Division Into Teams dp
- 4. Codeforces Round #598 (Div. 3) E - Yet Another Division Into Teams （劃分數-貪心-模擬）
- 5. Codeforces Round #595 (Div. 3)D1D2 貪心 STL
- 6. Codeforces Round #515 (Div. 3)-F. Yet another 2D Walking
- 7. Educational Codeforces Round 69 (Rated for Div. 2) D. Yet Another Subarray Problem 揹包dp
- 8. Educational Codeforces Round 86 (Rated for Div. 2) C. Yet Another Counting Problem
- 9. F. Yet another 2D Walking--Codeforces Round #515 (Div. 3)【dp】
- 10. codeforces 1288B Yet Another Meme Problem