shell判斷字符串相等腳本

#!/bin/sh

echo -n "login:"

read name

echo -n "password:"

read passwd

if [ "$name" = "aa" -a "$passwd" = "aaa" ];then

echo "right!"

else echo "error"

fi

一。運行過程當中出現過 [: missing `]'  的問題，是[ "$name" = "aa" -a "$passwd" = "aaa" ] "$name"前和"aaa"後都必需要有空格。

二。if裏面的-a至關因而與，-o至關因而或。還能夠用&&和||表達。

if [ "$name" = "aa" -a "$passwd" = "aaa" ];then  與

if [ "$name" = "aa" -o "$passwd" = "aaa" ];then  或

if [ "$name" = "aa" ] && [ "$passwd" = "aaa" ];then  與

if [ "$name" = "aa" ] || [ "$passwd" = "aaa" ];then  或

&&是shell自己的語法支持-a是shell的內部指令的用法