CXO的需求果真還在繼續,深呼吸,深呼吸 .......golang
有人說數據結構是爲算法服務的,我還要在加一句:數據結構和算法都是爲業務服務的!!算法
CXO的需求果真不一樣凡響,又讓菜菜想到了新的數據結構:棧c#
棧(stack)又名堆棧,它是一種運算受限的線性表。其限制是僅容許在表的一端進行插入和刪除運算。這一端被稱爲棧頂,相對地,把另外一端稱爲棧底。向一個棧插入新元素又稱做進棧、入棧或壓棧,它是把新元素放到棧頂元素的上面,使之成爲新的棧頂元素;從一個棧刪除元素又稱做出棧或退棧,它是把棧頂元素刪除掉,使其相鄰的元素成爲新的棧頂元素。數組
棧做爲一種數據結構,其中有幾個特性須要提起你們注意:bash
在內存分佈上棧是用是實現的呢?既然棧是一種線性結構,也就說能夠用線性的內存分佈數據結構來實現。數據結構
class MyStack
{
//數組容器
int[] container = new int[100];
//棧頂元素的索引
int TopIndex = -1;
//入棧操做
public void Push(int newValue)
{
if (TopIndex >= 99)
{
return ;
}
TopIndex++;
container[TopIndex] = newValue;
}
//出棧操做
public int Pop()
{
if (TopIndex < 0)
{
return 0;
}
var topValue = container[TopIndex];
TopIndex--;
return topValue;
}
}
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由以上能夠看出,棧實際上是基於基礎數據結構之上的一個具體業務形式的封裝即:先進後出。併發
基於數組的棧咱們暫且只討論未發生數組重建的場景下。不管是數組實現仍是鏈表實現,咱們發現棧的內部實際上是有一個指向棧頂元素的指針,不會發生遍歷數組或者鏈表的情形,因此棧的出棧操做時間複雜度爲O(1)。至於入棧,若是你看過我之前介紹數組和鏈表的文章,你能夠知道,給一個數組下標元素賦值的操做時間複雜度爲O(1),在鏈表頭部添加一個元素的操做時間複雜度也是O(1)。因此不管是數組仍是鏈表實現棧,入棧操做時間複雜度也是O(1)。而且棧只有入棧出棧兩種操做,比其餘數據結構有N個操做方法要簡單不少,也不容易出錯。 至於發生數組重建,copy所有數據的過程實際上是一個順序棧最壞的時間複雜度,由於和原數組的元素個數n有關,因此時間複雜度爲O(n)app
那一個計算器怎麼用棧來實現呢?其實不少編譯器就是經過兩個棧來實現的,其中一個棧保存操做的數,另外一個棧保存運算符。 咱們從左到右遍歷表達式,當遇到數字,咱們直接壓入操做數棧;當遇到操做符的時候,當前操做符與操做符棧頂的元素比較優先級(先乘除後加減的原則) 。若是當前運算符比棧頂運算符優先級高,那說明不須要執行棧頂運算符運算,咱們直接將當前運算符也入棧; 若是當前運算符比棧頂運算符優先級低,那說明該執行棧頂運算符的運算了。 而後出棧運算符棧頂元素,數據棧頂兩個元素,而後進行相關運算,而後把運算結果再次壓入數據棧。數據結構和算法
代碼寫的通常主要是演示棧的應用,特殊狀況下計算結果可能有誤,有興趣的同窗能夠重構一下函數
class Program
{
static void Main(string[] args)
{
List<string> lstAllData = new List<string>();
//讀取輸入的表達式,並整理
string inputStr = Console.ReadLine();
string tempData = "";
for (int i = 0; i < inputStr.Length; i++)
{
if (inputStr[i] == '+' || inputStr[i] == '-' || inputStr[i] == '*' || inputStr[i] == '/')
{
lstAllData.Add(tempData);
lstAllData.Add(inputStr[i].ToString());
tempData = "";
}
else
{
tempData += inputStr[i];
}
if(i== inputStr.Length - 1)
{
lstAllData.Add(tempData);
}
}
foreach (var item in lstAllData)
{
Calculator.Cal(item.ToString());
}
var ret = Calculator.GetResult();
Console.WriteLine(ret);
Console.Read();
}
}
//計算器
class Calculator
{
//存放計算數據的棧
static Stack<int> DataStack = new Stack<int>();
//存放操做符的棧
static Stack<string> OperatorStack = new Stack<string>();
public static int Cal(string dataOrOperator)
{
int data;
bool isData = int.TryParse(dataOrOperator, out data);
if (isData)
{
//若是是數據直接入數據棧
DataStack.Push(data);
}
else
{
//若是是操做符,和棧頂操做符比較優先級,若是大於棧頂,則直接入棧,不然棧頂元素出棧 進行操做
if (OperatorStack.Count <= 0)
{
OperatorStack.Push(dataOrOperator);
}
else
{
//當前運算符的優先級
var currentOpePrecedence = OperatorPrecedence(dataOrOperator);
//當前運算符棧頂元素的優先級
var stackTopOpePrecedence = OperatorPrecedence(OperatorStack.Peek());
if (currentOpePrecedence > stackTopOpePrecedence)
{
//若是當前運算符的優先級大於棧頂元素的優先級,則入棧
OperatorStack.Push(dataOrOperator);
}
else
{
//運算符棧頂元素出棧,數據棧出棧兩個元素,而後進行運算
var stackOpe = OperatorStack.Pop();
var data2 = DataStack.Pop();
var data1 = DataStack.Pop();
var ret = CalculateData(stackOpe, data1, data2);
DataStack.Push(ret);
OperatorStack.Push(dataOrOperator);
}
}
}
return 0;
}
//獲取表達式最後的計算結果
public static int GetResult()
{
var ret = 0;
while (OperatorStack.Count > 0)
{
var stackOpe = OperatorStack.Pop();
var data2 = DataStack.Pop();
var data1 = DataStack.Pop();
ret = CalculateData(stackOpe, data1, data2);
DataStack.Push(ret);
}
return ret;
}
//根據操做符進行運算,這裏能夠抽象出接口,請自行實現
static int CalculateData(string operatorString, int data1, int data2)
{
switch (operatorString)
{
case "+":
return data1 + data2;
case "-":
return data1 - data2;
case "*":
return data1 * data2;
case "/":
return data1 + data2;
default:
return 0;
}
}
//獲取運算符優先級
public static int OperatorPrecedence(string a) //操做符優先級
{
int i = 0;
switch (a)
{
case "+": i = 1; break;
case "-": i = 1; break;
case "*": i = 2; break;
case "/": i = 2; break;
}
return i;
}
}
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運行結果:
10+20*3+10-10+20-20+60*2
190
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package stack
import (
"errors"
"fmt"
)
type Stack struct {
Element []interface{} //Element
}
func NewStack() *Stack {
return &Stack{}
}
func (stack *Stack) Push(value ...interface{}) {
stack.Element = append(stack.Element, value...)
}
//返回下一個元素
func (stack *Stack) Top() (value interface{}) {
if stack.Size() > 0 {
return stack.Element[stack.Size()-1]
}
return nil //read empty stack
}
//返回下一個元素,並從Stack移除元素
func (stack *Stack) Pop() (value interface{}) {
if stack.Size() > 0 {
d := stack.Element[stack.Size()-1]
stack.Element = stack.Element[:stack.Size()-1]
return d
}
return nil
}
//交換值
func (stack *Stack) Swap(other *Stack) {
switch {
case stack.Size() == 0 && other.Size() == 0:
return
case other.Size() == 0:
other.Element = stack.Element[:stack.Size()]
stack.Element = nil
case stack.Size() == 0:
stack.Element = other.Element
other.Element = nil
default:
stack.Element, other.Element = other.Element, stack.Element
}
return
}
//修改指定索引的元素
func (stack *Stack) Set(idx int, value interface{}) (err error) {
if idx >= 0 && stack.Size() > 0 && stack.Size() > idx {
stack.Element[idx] = value
return nil
}
return errors.New("Set失敗!")
}
//返回指定索引的元素
func (stack *Stack) Get(idx int) (value interface{}) {
if idx >= 0 && stack.Size() > 0 && stack.Size() > idx {
return stack.Element[idx]
}
return nil //read empty stack
}
//Stack的size
func (stack *Stack) Size() int {
return len(stack.Element)
}
//是否爲空
func (stack *Stack) Empty() bool {
if stack.Element == nil || stack.Size() == 0 {
return true
}
return false
}
//打印
func (stack *Stack) Print() {
for i := len(stack.Element) - 1; i >= 0; i-- {
fmt.Println(i, "=>", stack.Element[i])
}
}
package calculator
import (
"calculator/stack"
"strconv"
)
type Calculator struct{}
var DataStack *stack.Stack
var OperatorStack *stack.Stack
func NewCalculator() *Calculator {
DataStack = stack.NewStack()
OperatorStack = stack.NewStack()
return &Calculator{}
}
func (c *Calculator) Cal(dataOrOperator string) int {
if data, ok := strconv.ParseInt(dataOrOperator, 10, 64); ok == nil {
//若是是數據直接入數據棧
// fmt.Println(dataOrOperator)
DataStack.Push(data)
} else {
//若是是操做符,和棧頂操做符比較優先級,若是大於棧頂,則直接入棧,不然棧頂元素出棧 進行操做
if OperatorStack.Size() <= 0 {
OperatorStack.Push(dataOrOperator)
} else {
//當前運算符的優先級
currentOpePrecedence := operatorPrecedence(dataOrOperator)
//當前運算符棧頂元素的優先級
stackTopOpePrecedence := operatorPrecedence(OperatorStack.Top().(string))
if currentOpePrecedence > stackTopOpePrecedence {
//若是當前運算符的優先級大於棧頂元素的優先級,則入棧
OperatorStack.Push(dataOrOperator)
} else {
//運算符棧頂元素出棧,數據棧出棧兩個元素,而後進行運算
stackOpe := OperatorStack.Pop()
data2 := DataStack.Pop()
data1 := DataStack.Pop()
ret := calculateData(stackOpe.(string), data1.(int64), data2.(int64))
DataStack.Push(ret)
OperatorStack.Push(dataOrOperator)
}
}
}
return 0
}
func (c *Calculator) GetResult() int64 {
var ret int64
for {
if OperatorStack.Size() > 0 {
stackOpe := OperatorStack.Pop()
data2 := DataStack.Pop()
data1 := DataStack.Pop()
ret = calculateData(stackOpe.(string), data1.(int64), data2.(int64))
DataStack.Push(ret)
} else {
break
}
}
return ret
}
func calculateData(operatorString string, data1, data2 int64) int64 {
switch operatorString {
case "+":
return data1 + data2
case "-":
return data1 - data2
case "*":
return data1 * data2
case "/":
return data1 + data2
default:
return 0
}
}
func operatorPrecedence(a string) int {
i := 0
switch a {
case "+":
i = 1
case "-":
i = 1
case "*":
i = 2
case "/":
i = 2
}
return i
}
package main
import (
"calculator/calculator"
"flag"
"fmt"
)
var (
inputStr = flag.String("input", "", "請輸入...")
)
func main() {
flag.Parse()
var lstAllData []string
var tempData string
rs := []rune(*inputStr)
for i := 0; i < len(rs); i++ {
if string(rs[i]) == "+" || string(rs[i]) == "-" || string(rs[i]) == "*" || string(rs[i]) == "/" {
lstAllData = append(lstAllData, tempData)
lstAllData = append(lstAllData, string(rs[i]))
tempData = ""
} else {
tempData += string(rs[i])
}
if i == len(rs)-1 {
lstAllData = append(lstAllData, tempData)
}
}
ca := calculator.NewCalculator()
for _, v := range lstAllData {
ca.Cal(v)
}
ret := ca.GetResult()
fmt.Println(ret)
}
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運算結果:
go run program.go -input=1+2-1*3
結果:0
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