Python批量針對每一個文件打zip包

Python

# importing required modules
from zipfile import ZipFile
import os


def get_all_file_paths(directory):
    # initializing empty file paths list
    file_paths = []

    # crawling through directory and subdirectories
    for root, directories, files in os.walk(directory):
        for filename in files:
            # join the two strings in order to form the full filepath.
            filepath = os.path.join(root, filename)
            file_paths.append(filepath)

            # returning all file paths
    return file_paths


def main():
    # path to folder which needs to be zipped
    directory = '/Users/zhangyalin/Music/mp3/'

    # calling function to get all file paths in the directory
    file_paths = get_all_file_paths(directory)

    # printing the list of all files to be zipped
    print('Following files will be zipped:')
    for file in file_paths:
        print(file)
        # writing files to a zipfile
        with ZipFile('{0}.zip'.format(file), 'w') as zip:
            # writing each file one by one
            zip.write(file, arcname=os.path.basename(file))
    print('All files zipped successfully!')


if __name__ == "__main__":
    main()

參考

• Working with zip files in Python
• 10.1. os.path — Common pathname manipulations¶