用SQL語句,刪除掉重複項只保留一條mysql
在幾千條記錄裏,存在着些相同的記錄,如何能用SQL語句,刪除掉重複的呢sql
請留意紅色部分bash
SELECT
*
FROM
people
WHERE
peopleId IN (
SELECT
peopleId
FROM
people
GROUP BY
peopleId
HAVING
count(peopleId) > 1
)
複製代碼
DELETE
FROM
people
WHERE
peopleName IN (
SELECT
peopleName
FROM
people
GROUP BY
peopleName
HAVING
count(peopleName) > 1
)
AND peopleId NOT IN (
SELECT
min(peopleId)
FROM
people
GROUP BY
peopleName
HAVING
count(peopleName) > 1
)
複製代碼
執行報錯:1093 - You can't specify target table 'student' for update in FROM clause 緣由是:更新數據時使用了查詢,而查詢的數據又作了更新的條件,mysql不支持這種方式。 怎麼規避這個問題? 再加一層封裝,以下:spa
DELETE
FROM
people
WHERE
peopleName IN (
SELECT
peopleName
FROM(
SELECT
peopleName
FROM
people
GROUP BY
peopleName
HAVING
count(peopleName) > 1
) a
)
AND peopleId NOT IN (
SELECT
peopleName
FROM(
SELECT
min(peopleId)
FROM
people
GROUP BY
peopleName
HAVING
count(peopleName) > 1
) b
)
複製代碼
SELECT
*
FROM
vitae a
WHERE
(a.peopleId, a.seq) IN (
SELECT
peopleId,
seq
FROM
vitae
GROUP BY
peopleId,
seq
HAVING
count(*) > 1
)
複製代碼
DELETE
FROM
vitae a
WHERE
(a.peopleId, a.seq) IN (
SELECT
peopleId,
seq
FROM
vitae
GROUP BY
peopleId,
seq
HAVING
count(*) > 1
)
AND rowid NOT IN (
SELECT
min(rowid)
FROM
vitae
GROUP BY
peopleId,
seq
HAVING
count(*) > 1
)
複製代碼
SELECT
*
FROM
vitae a
WHERE
(a.peopleId, a.seq) IN (
SELECT
peopleId,
seq
FROM
vitae
GROUP BY
peopleId,
seq
HAVING
count(*) > 1
)
AND rowid NOT IN (
SELECT
min(rowid)
FROM
vitae
GROUP BY
peopleId,
seq
HAVING
count(*) > 1
)
複製代碼
UPDATE tableName
SET [ Title ]= RIGHT ([ Title ],(len([ Title ]) - 1))
WHERE
Title LIKE '村%'
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UPDATE tableName
SET [ Title ]= LEFT ([ Title ],(len([ Title ]) - 1))
WHERE
Title LIKE '%村'
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UPDATE tableName
SET key = value WHERE key1 IN (
SELECT key1 FROM vitae GROUP BY peopleId)
複製代碼