牛客網-華爲-2020屆校園招聘上機考試-1

題目描述: 給定一個數組,裏面有6個整數,求這個數組可以表示的最大24進制時間是多少,輸出這個時間,沒法表示輸出invalid。ios

輸入描述: 輸入爲一個整數數組,數組內有六個整數。 輸入整數數組長度爲6,不須要考慮它長度,元素爲0或者正整數,6個數字每一個數字只能使用一次;數組

輸出描述: 輸出爲一個24進制格式的時間,或者字符串「invalid」。spa

示例1 輸入 [0,2,3,0,5,6] 輸出 23:56:00.net

示例1 輸入 [9,9,9,9,9,9] 輸出 invalid <br><br>code

1.思考blog

  • 首先想到的就是按照時、分、秒的狀況都分析一遍,獲得最大的時間;
  • 時最大不超過23,分十位爲2和小於2兩種狀況分析,十位爲2則個位不大於3,十位小於2則個位不大於9;
  • 分最大不超過59,十位不大於5,個位不大於9;
  • 秒最大不超過59,十位不大於5,個位不大於9。<br><br>

2.實現ci

<br>字符串

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;

vector<int> CompTime(vector<int>& num){
	vector<int> time;

	//Invalid
	if (num[3] > 5 || num[1] > 3 || num[0] > 2){
		time.clear();
		return time;
	}

	//Hour
	bool hflag = false;
	int len = num.size();
	int a, b;
	for (int i = len - 1; i >= 0; i--){
		if (num[i] < 2){
			a = i;
			time.push_back(num[i]);
			for (int j = len - 1; j >= 0; j--){
				if (num[j] <= 9 && j != i){
					b = j;
					hflag = true;
					time.push_back(num[j]);
					break;
				}
			}
			if (hflag){
				num.erase(num.begin() + max(a, b));
				num.erase(num.begin() + min(a, b));
				break;
			}
		}
		else if (num[i] == 2){
			a = i;
			time.push_back(num[i]);
			for (int j = len - 1; j >= 0; j--){
				if (num[j] < 4 && j != i){
					b = j;
					hflag = true;
					time.push_back(num[j]);
					break;
				}
			}
			if (hflag){
				num.erase(num.begin() + max(a, b));
				num.erase(num.begin() + min(a, b));
				break;
			}
		}
	}
	if (hflag == false){
		time.clear();
		return time;
	}

	//Minute
	len = num.size();
	bool mflag = false;
	for (int i = len - 1; i >= 0; i--){
		if (num[i] <= 5){
			a = i;
			time.push_back(num[i]);
			for (int j = len - 1; j >= 0; j--){
				if (num[j] <= 9){
					b = j;
					mflag = true;
					time.push_back(num[j]);
					break;
				}
			}
			if (mflag){
				num.erase(num.begin() + max(a, b));
				num.erase(num.begin() + min(a, b));
				break;
			}
		}
	}
	if (mflag == false){
		time.clear();
		return time;
	}

	//Second
	bool sflag = false;
	if (num[1] <= 5){
		sflag = true;
		time.push_back(num[1]);
		time.push_back(num[0]);
	}
	else if (num[0] <= 5){
		sflag = true;
		time.push_back(num[0]);
		time.push_back(num[1]);
	}
	
	if (sflag == false){
		time.clear();
	}

	return time;
}

int main(){
	string input;

	while (getline(cin, input)){
		vector<int> num, time;		
		for (int i = 1; i < 12; i=i+2){
			num.push_back(input[i] - '0');
		}

		sort(num.begin(), num.end());		
		time = CompTime(num);

		if (time.empty()){
			cout << "invalid" << endl;
		}
		else{
			cout << time[0] << time[1] << ":" << time[2] << time[3] << ":" << time[4] << time[5] << endl;
		}

	}

	return 0;
}
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