Educational Codeforces Round 91 (Rated for Div. 2)題解
A. Three Indices 題目連接 https://codeforces.com/contest/1380/problem/Aios 思路 直接遍歷數組找到一個值比它左右的值都大的便可 緣由：若是該值存在，則該點一定爲最大值，左右的值至少有一個比它小c++ 代碼 #include<cstdio>
#include<iostream>
#include<math.h>
using names
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相關文章
- 1. Educational Codeforces Round 91 (Rated for Div. 2)
- 2. Educational Codeforces Round 61 (Rated for Div. 2)(題解)
- 3. Educational Codeforces Round 92 (Rated for Div. 2)題解
- 4. Educational Codeforces Round 90 (Rated for Div. 2)題解
- 5. Educational Codeforces Round 47 (Rated for Div. 2) 題解
- 6. 【A題】Educational Codeforces Round 83 (Rated for Div. 2)
- 7. Educational Codeforces Round 67 (Rated for Div. 2)
- 8. Educational Codeforces Round 77 (Rated for Div. 2)
- 9. Educational Codeforces Round 86 (Rated for Div. 2) A~D
- 10. Educational Codeforces Round 86 [Rated for Div. 2] Solution