舉例說明:
1、當兩個併發線程訪問同一個對象object中的這個synchronized(this)同步代碼塊時,一個時間內只能有一個線程獲得執行。另外一個線程必須等待當前線程執行完這個代碼塊之後才能執行該代碼塊。併發
package ths;oop
public class Thread1 implements Runnable {
public void run() {
synchronized(this) {
for (int i = 0; i < 5; i++) {
System.out.println(Thread.currentThread().getName() + " synchronized loop " + i);
}
}
}
public static void main(String[] args) {
Thread1 t1 = new Thread1();
Thread ta = new Thread(t1, "A");
Thread tb = new Thread(t1, "B");
ta.start();
tb.start();
}
}this
結果:
A synchronized loop 0
A synchronized loop 1
A synchronized loop 2
A synchronized loop 3
A synchronized loop 4
B synchronized loop 0
B synchronized loop 1
B synchronized loop 2
B synchronized loop 3
B synchronized loop 4線程
2、然而,當一個線程訪問object的一個synchronized(this)同步代碼塊時,另外一個線程仍然能夠訪問該object中的非synchronized(this)同步代碼塊。對象
package ths;get
public class Thread2 {
public void m4t1() {
synchronized(this) {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}
}
public void m4t2() {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}
public static void main(String[] args) {
final Thread2 myt2 = new Thread2();
Thread t1 = new Thread( new Runnable() { public void run() { myt2.m4t1(); } }, "t1" );
Thread t2 = new Thread( new Runnable() { public void run() { myt2.m4t2(); } }, "t2" );
t1.start();
t2.start();
}
}同步
結果:
t1 : 4
t2 : 4
t1 : 3
t2 : 3
t1 : 2
t2 : 2
t1 : 1
t2 : 1
t1 : 0
t2 : 0io
3、尤爲關鍵的是,當一個線程訪問object的一個synchronized(this)同步代碼塊時,其餘線程對object中全部其它synchronized(this)同步代碼塊的訪問將被阻塞。class
//修改Thread2.m4t2()方法:
public void m4t2() {
synchronized(this) {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}object
}
結果:
t1 : 4
t1 : 3
t1 : 2
t1 : 1
t1 : 0
t2 : 4
t2 : 3
t2 : 2
t2 : 1
t2 : 0
4、第三個例子一樣適用其它同步代碼塊。也就是說,當一個線程訪問object的一個synchronized(this)同步代碼塊時,它就得到了這個object的對象鎖。結果,其它線程對該object對象全部同步代碼部分的訪問都被暫時阻塞。
//修改Thread2.m4t2()方法以下:
public synchronized void m4t2() {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}
結果:
t1 : 4
t1 : 3
t1 : 2
t1 : 1
t1 : 0
t2 : 4
t2 : 3
t2 : 2
t2 : 1
t2 : 0
5、以上規則對其它對象鎖一樣適用:
package ths;
public class Thread3 {
class Inner {
private void m4t1() {
int i = 5;
while(i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : Inner.m4t1()=" + i);
try {
Thread.sleep(500);
} catch(InterruptedException ie) {
}
}
}
private void m4t2() {
int i = 5;
while(i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : Inner.m4t2()=" + i);
try {
Thread.sleep(500);
} catch(InterruptedException ie) {
}
}
}
}
private void m4t1(Inner inner) {
synchronized(inner) { //使用對象鎖
inner.m4t1();
}
private void m4t2(Inner inner) {
inner.m4t2();
}
public static void main(String[] args) {
final Thread3 myt3 = new Thread3();
final Inner inner = myt3.new Inner();
Thread t1 = new Thread( new Runnable() {public void run() { myt3.m4t1(inner);} }, "t1");
Thread t2 = new Thread( new Runnable() {public void run() { myt3.m4t2(inner);} }, "t2");
t1.start();
t2.start();
}
}
結果:
儘管線程t1得到了對Inner的對象鎖,但因爲線程t2訪問的是同一個Inner中的非同步部分。因此兩個線程互不干擾。
t1 : Inner.m4t1()=4
t2 : Inner.m4t2()=4
t1 : Inner.m4t1()=3
t2 : Inner.m4t2()=3
t1 : Inner.m4t1()=2
t2 : Inner.m4t2()=2
t1 : Inner.m4t1()=1
t2 : Inner.m4t2()=1
t1 : Inner.m4t1()=0
t2 : Inner.m4t2()=0
如今在Inner.m4t2()前面加上synchronized:
private synchronized void m4t2() {
int i = 5;
while(i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : Inner.m4t2()=" + i);
try {
Thread.sleep(500);
} catch(InterruptedException ie) {
}
}
}
結果:
儘管線程t1與t2訪問了同一個Inner對象中兩個絕不相關的部分,但由於t1先得到了對Inner的對象鎖,因此t2對Inner.m4t2()的訪問也被阻塞,由於m4t2()是Inner中的一個同步方法。
t1 : Inner.m4t1()=4 t1 : Inner.m4t1()=3 t1 : Inner.m4t1()=2 t1 : Inner.m4t1()=1 t1 : Inner.m4t1()=0 t2 : Inner.m4t2()=4 t2 : Inner.m4t2()=3 t2 : Inner.m4t2()=2 t2 : Inner.m4t2()=1 t2 : Inner.m4t2()=0