MIT_單變量微積分_19

1.定積分在對數和幾何上的應用 FTC2: d d x ∫ a x f ( t ) d ( t ) = f ( x ) y ′ = 1 x ; L ( x ) = ∫ 1 x d t t L ′ ( x ) = 1 x ; L ( x ) = ∫ 1 1 d t t = 0 L ′ ′ = − 1 x 2 L ( 1 ) = 0 ; L ′ ( 1 ) = 1 \frac{d}{dx}\int_a

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