c#生成相似Mongodb的ObjectId有序、不重複Guid

private static DateTime dt1970 = new DateTime(1970, 1, 1); private static Random rnd = new Random(); private static readonly int __staticMachine = ((0x00ffffff & Environment.MachineName.GetHashCode()) +
#if NETSTANDARD1_5 || NETSTANDARD1_6
    1
#else AppDomain.CurrentDomain.Id #endif ) & 0x00ffffff; private static readonly int __staticPid = Process.GetCurrentProcess().Id; private static int __staticIncrement = rnd.Next(); /// <summary>
/// 生成相似Mongodb的ObjectId有序、不重複Guid /// </summary>
/// <returns></returns>
public static Guid NewMongodbId() { var now = DateTime.Now; var uninxtime = (int) now.Subtract(dt1970).TotalSeconds; int increment = Interlocked.Increment(ref __staticIncrement) & 0x00ffffff; var rand = rnd.Next(0, int.MaxValue); var guid = $"{uninxtime.ToString("x8").PadLeft(8, '0')}{__staticMachine.ToString("x8").PadLeft(8, '0').Substring(2, 6)}{__staticPid.ToString("x8").PadLeft(8, '0').Substring(6, 2)}{increment.ToString("x8").PadLeft(8, '0')}{rand.ToString("x8").PadLeft(8, '0')}"; return Guid.Parse(guid); } //代碼來自 dotnetGen //https://github.com/2881099/dotnetGen_postgresql
//https://github.com/2881099/dotnetGen_mysql
//https://github.com/2881099/dotnetGen_sqlserver