post方法名及參數爲:(具體方法可參考http://www.javashuo.com/article/p-nseguyln-a.html)html
public static String doPost(String httpUrl, String param) { ... }
若是方法參數param是要求以json字符串的形式傳遞則:json
1. 若是是JSONObject對象轉字符串則:String result = HttpUtil.doPost(URL, json.toJsonString());post
2. Map轉字符串則需採用:String result = HttpUtil.doPost(URL, JSON.toJSONString(map));測試
注:使用map.toString() 時會出現參數解析不到的問題spa
由於:json.toJsonString()轉換後爲:{"name":"ceshi","password":"123456"}code
map.toString()轉換後爲:{password=123456, name=ceshi}htm
對比可知,參數不一致;對象
測試以下:blog
public static void main(String[] args) { Map map = new HashMap<>(); map.put("name", "ceshi"); map.put("password", "123456"); System.out.println(map.toString()); //{password=123456, name=ceshi} System.out.println(JSON.toJSONString(map)); //{"name":"ceshi","password":"123456"} JSONObject json = new JSONObject(); json.put("name", "ceshi"); json.put("password", "123456"); System.out.println(json.toJSONString()); //{"name":"ceshi","password":"123456"} }