Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not.node
You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.git
Example 1:github
Input: Tree 1 Tree 2 1 2 / \ / \ 3 2 1 3 / \ \ 5 4 7 Output: Merged tree: 3 / \ 4 5 / \ \ 5 4 7
Note: The merging process must start from the root nodes of both trees.app
遇到樹問題,首先想到遞歸code
將t2的val加到t1,返回當前處理的t1結點遞歸
若是t1爲null,把引用指向t2leetcode
須要注意處理null的問題get
# Definition for a binary tree node. class TreeNode(object): def __init__(self, x): self.val = x self.left = None self.right = None class Solution(object): def mergeTrees(self, t1, t2): """ :type t1: TreeNode :type t2: TreeNode :rtype: TreeNode """ if t1 is not None and t2 is not None: t1.val += t2.val t1.left = self.mergeTrees(t1.left, t2.left) t1.right = self.mergeTrees(t1.right, t2.right) elif t1 is None and t2 is not None: t1 = t2 return t1
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