Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.this
For example,
Given nums = [0, 1, 3]
return 2
.spa
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?code
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.orm
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class Solution { public: int missingNumber(vector<int>& nums) { int totalSum = nums.size()*(1+nums.size())/2; int thiSum = accumulate(nums.begin(), nums.end(), 0); return totalSum-thiSum; } };