D. Almost All Divisors
http://codeforces.com/contest/1165/problem/Dc++ #include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll a[2000200],f,t,n,l,r,ans;
int main() {
scanf("%lld", &t);
while (t--) {
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相關文章
- 1. Almost All Divisors（求因子個數及思惟）
- 2. CF888 D. Almost Identity Permutations（數學）
- 3. Andrew Stankevich Contest 10 D More Divisors 反素數
- 4. 8 Summing divisors
- 5. B. Divisors of Two Integers
- 6. Xenia and Divisors
- 7. Almost differential privacy
- 8. Almost-Famous
- 9. Educational Codeforces Round 89 (Rated for Div. 2)D. Two Divisors
- 10. codeforces 301D Yaroslav and Divisors