[leetcode]Palindrome Number

class Solution {
public:
    bool isPalindrome(int x) {
        if(x < 0) return false;
        if(x < 10) return true;
        int temp1;
        int temp2;
        int dx = 0;
        int t = x;
        while(t != 0)
        {
            t = t/10;
            ++dx;
        }
        
        t = x;
        int left = pow(10, dx - 1); 
        
        while(t != 0)
        {
            temp1 = t % 10;
            t = t /10;
            
            temp2 = x / left % 10;
            
            if(temp1 == temp2)
            {
                left = left/10;
            }
            else
            return false;
            
        }
        return true;

    }
};

View Code

Palindrome Number

不能開闢新的內存，所以只能經過取模等運算。還算簡單。