三項式展開

求（x+y+z）^n各個展開的係數，和冪 1<n<=15  k1+k2+k3=n #include<cstdio> #include<iostream> using namespace std; long long fac[] = {1,1,2,6,24,120,720,5040,40320,362880,3628800,39916800,479001600,6227020800,8717829

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