python實現買啤酒（2元一瓶，4個瓶蓋換一瓶，2個瓶子換一瓶）

題目：啤酒2元一瓶，4個瓶蓋換一瓶，2個瓶子換一瓶，問10元錢能喝幾瓶？

把生活中的事情轉換成代碼，咱們首先要作的是找出事情的規律：

　　喝酒產生瓶蓋和瓶子，瓶蓋和瓶子又能換酒，酒又產生瓶蓋和瓶子，如此不斷循環，那麼就很容易讓人想到遞歸。只要對細節稍加控制，就能夠完成計算了。

代碼以下：

#!/usr/bin/env python3
# -*- coding:utf-8 -*-
count = 0
surplus_bottleTop = 0
surplus_bottle = 0
def drinkAndSurplus(bottleTop, bottle):
    global count,surplus_bottleTop,surplus_bottle
    beers = 0
    beers += bottleTop//4
    beers += bottle//2
    count += beers
    bottleTop = bottleTop%4 + beers
    bottle = bottle%2 + beers
    print('本次喝了%d瓶，剩餘瓶蓋%d個，剩餘瓶子%d個'%(beers, bottleTop, bottle))
    if(bottleTop//4 > 0 or bottle//2 > 0):
        drinkAndSurplus(bottleTop, bottle)
    else:
        surplus_bottleTop = bottleTop
        surplus_bottle = bottle
if __name__ == '__main__':
    money = 10
    count, surplus_bottleTop, surplus_bottle = money//2, money//2, money//2
    print('總共%d元錢,本次喝酒%d瓶，剩餘瓶蓋%d個，剩餘瓶子%d個'%(money,count,count,count))
    drinkAndSurplus(surplus_bottleTop, surplus_bottle)
    print('總共喝了%d瓶，剩餘瓶蓋%d個，剩餘瓶子%d個'%(count,surplus_bottleTop,surplus_bottle))

 

執行結果以下：

python新手，大神勿噴！