柯里化手寫實現

參考：https://www.cnblogs.com/liuXiaoDi/p/12615860.html

使用arguments和arguments.callee

function myCurrying(fn) {
    const vars = [];
    if (arguments.length > 0) {
        // vars.concat(Array.from(arguments));
        vars = [...vars, ...arguments];
        return arguments.callee;
    } else {
        return fn.apply(null, vars);
    }
}

其餘思路

• 1.手寫jsonp

jsonp(url, data, callback) {
    
}

參考:http://www.javashuo.com/article/p-fwlpsrks-gk.html

• 2.通用柯里化函數

currying(func) {
    // return function: func(a1, a2, a3, ...) -> func_c(a1)(a2)(a3)...
}

• 2.手寫柯里化函數 -柯里化在工程中有什麼用處？

https://www.zhihu.com/answer/192978122

• 詳解JS函數的柯里化：https://www.jianshu.com/p/2975c25e4d71

柯里化實現與問題：

// (1) sum(a1)...(an)()
var currying = function(func) {
  const args = [];
  return function result(...rest) {
    if (rest.length === 0) {
      return func(...args)
    }
    args.push(...rest)
    return result
  }
}

// (2) sum(a1)...(an) ?

// (3) new_func = curry(func); new_func(x1)(x2)(),再new_func(y1)(y2)(y3)()，怎樣保證兩次互不影響

var currying = function(func) {
  let args = [];
  return function result(...rest) {
    if (rest.length === 0) {
      ans = func(...args)
      args = [];
      return ans;
    }
    args.push(...rest)
    return result
  }
}