//方法一:用JAVA自帶的函數
public static boolean isNumeric(String str){
for (int i = str.length();--i>=0;){
if (!Character.isDigit(str.charAt(i))){
return false;
}
}
return true;
}git
/*方法二:推薦,速度最快
* 判斷是否爲整數
* @param str 傳入的字符串
* @return 是整數返回true,不然返回false
*/函數
public static boolean isInteger(String str) {
Pattern pattern = Pattern.compile("^[-\\+]?[\\d]*$");
return pattern.matcher(str).matches();
}.net
//方法三: public static boolean isNumeric(String str){ Pattern pattern = Pattern.compile("[0-9]*"); return pattern.matcher(str).matches(); }
//方法四:
public final static boolean isNumeric(String s) {
if (s != null && !"".equals(s.trim()))
return s.matches("^[0-9]*$");
else
return false;
}對象
//方法五:用ascii碼
public static boolean isNumeric(String str){
for(int i=str.length();--i>=0;){
int chr=str.charAt(i);
if(chr<48 || chr>57)
return false;
}
return true;
}ci
經過HashSet踢除重複元素element
public static List removeDuplicate(List list) {
HashSet h = new HashSet(list);
list.clear();
list.addAll(h);
return list;
}rem
循環list中的全部元素而後刪除重複字符串
public static List removeDuplicate(List list) {
for ( int i = 0 ; i < list.size() - 1 ; i ++ ) {
for ( int j = list.size() - 1 ; j > i; j -- ) {
if (list.get(j).equals(list.get(i))) {
list.remove(j);
}
}
}
return list;
}get
刪除ArrayList中重複元素,保持順序
public static void removeDuplicateWithOrder(List list) {
Set set = new HashSet();
List newList = new ArrayList();
for (Iterator iter = list.iterator(); iter.hasNext();) {
Object element = iter.next();
if (set.add(element))
newList.add(element);
}
list.clear();
list.addAll(newList);
System.out.println( " remove duplicate " + list);
}it
把list裏的對象遍歷一遍,用list.contain(),若是不存在就放入到另一個list集合中
public static List removeDuplicate(List list){ List listTemp = new ArrayList(); for(int i=0;i<list.size();i++){ if(!listTemp.contains(list.get(i))){ listTemp.add(list.get(i)); } } return listTemp; }