SQL查詢：獲取一個時間段內的全部日期

select level,to_char(to_date('2019-07-01','yyyy-mm-dd')+level-1,'yyyy-mm-dd') as abnormal_date from dual connect by level <=to_date('2019-08-01','yyyy-mm-dd')-to_date('2019-07-01','yyyy-mm-dd')+1

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