一、數組(Array)算法
數組是一個有相同數據類型的元素組成的固定長度的有序集合,如:var x [5]int,使用var定義的數組,默認值若是整型爲0,浮點型爲0.0,字符串爲"",對象爲nil。數組
求整型數組之和,使用range函數,遍歷數組、切片、字典時,返回索引和元素值;當對某個返回值不感興趣時,要用下劃線(_)來代替app
package main import "fmt" func main() { var x [5]int x[0] = 2 x[1] = 3 x[2] = 3 var sum int for _, elem := range x { sum += elem } fmt.Println(sum) }
定義數組其餘方式:1)、var x = [5]int{1,2,3,4,5}函數
2)、var x =[5]int{}測試
x[0]=1spa
3)、var x = [...]string{ var x = [...]string{
"Monday", "Monday", 3d
"Tuesday" "Tuesday",//能夠帶着英文逗號
} }code
二、切片(Slice)對象
切片相似數組,切片長度是可變的;切片是有容量(capacity)和長度(length)兩個屬性的;切片變量使用時,索引不能大於等於切片長度,不然報錯out of rangeblog
1)、make函數定義切片
package main import "fmt" func main() { var x = make([]float64, 5) //切片的容量和長度都是5 fmt.Println("Capacity:", cap(x), "Length:", len(x)) var y = make([]float64, 5, 10) //切片容量爲10,長度爲5 fmt.Println("Capacity:", cap(y), "Length:", len(y)) for i := 0; i < len(x); i++ { x[i] = float64(i) } fmt.Println(x) for i := 0; i < len(y); i++ { y[i] = float64(i) } fmt.Println(y) }
輸出如圖:
2)、經過數組切片賦值,採用[low_index:high_index]方式截取數組來獲取數值切片,其中獲取包括low_index,不包括high_index,high_index不能大於數組長度
使用案例以下
package main import "fmt" func main() { var arr1 = [5]int{1, 2, 3, 4, 5} var s1 = arr1[2:3] var s2 = arr1[:3] var s3 = arr1[2:] var s4 = arr1[:] fmt.Println(s1) fmt.Println(s2) fmt.Println(s3) fmt.Println(s4) }
運行結果以下
3)、切片長度可變性,使用append函數
package main import "fmt" func main() { var arr1 = make([]int, 5, 10) for i := 0; i < len(arr1); i++ { arr1[i] = i } fmt.Println(arr1) arr1 = append(arr1, 5, 6, 7, 8, 9, 10) fmt.Println("Capacity:", cap(arr1), "Length:", len(arr1)) fmt.Println(arr1) }
運行結果如圖,可知切片擴容算法是原來容量大小的兩倍;在測試代碼中發現,若是追加元素超過兩倍容量,後面擴容算法就不會是倍數擴容了
4)、copy函數,複製切片中元素
package main import "fmt" func main() { slice1 := []int{1, 2, 3, 4, 5, 6} slice2 := make([]int, 5, 10) copy(slice2, slice1) fmt.Println(slice1) fmt.Println(slice2) }
運行結果以下,slice2長度爲5,因此只拷貝了slice1的前五個元素
5)、小總結一下,使用 := 方式定義切片,和數組區別僅僅是方括號[]中是否有數字或 ...
示例以下,輸出結果都是:[1 2 3 4]
package main import "fmt" func main() { arr1 := [4]int{1, 2, 3, 4} fmt.Println(arr1) arr2 := [...]int{1, 2, 3, 4} fmt.Println(arr2) arr3 := []int{1, 2, 3, 4} fmt.Println(arr3) }
三、字典(Map)
字典是一組無序的,鍵值對的集合,字典也叫關聯數組,數組經過索引取數,字典經過鍵來取數
1)、初始化數據方式定義字典
package main import "fmt" func main() { var x = map[string]string{ "A": "Apple", "B": "Banana", "O": "Orange", "P": "Pear", } for key, val := range x { fmt.Println("Key:", key, "Value:", val) } }
運行結果
2)、make函數定義map,若是隻定義,不初始化,使用會報錯
package main import "fmt" func main() { var x map[string]string //定義map x = make(map[string]string) //初始化map x["A"] = "Apple" x["B"] = "Banana" x["O"] = "Orange" x["P"] = "Peer" for key, val := range x { fmt.Println("Key:", key, "Value:", val) } }
3)、使用 := 定義並初始化map
package main import "fmt" func main() { x := make(map[string]string) x["A"] = "Apple" x["B"] = "Banana" x["O"] = "Orange" x["P"] = "Peer" for key, val := range x { fmt.Println("Key:", key, "Value:", val) } }
4)、獲取字典中不存在的key值,若是是整數則返回0,字符串返回 "";這樣的返回值,若是map中就是有值爲0或空字符串,就沒法區分了
使用 := 能夠獲取map中元素值和是否存在的布爾類型,以下
package main import "fmt" func main() { x := make(map[string]int) x["A"] = 0 x["B"] = 1 val1, ok1 := x["C"] fmt.Println(val1) fmt.Println(ok1) val2, ok2 := x["A"] fmt.Println(val2) fmt.Println(ok2) }
運行結果
在實際使用中,能夠以下判斷是否含有key值
package main import "fmt" func main() { x := make(map[string]int) x["A"] = 0 x["B"] = 1 if val, ok := x["C"]; ok { fmt.Println(val) }else{ fmt.Println("不存在") } }
輸出以下
5)、map中使用delete函數刪除元素,若是不存在,刪除也不會報錯,不會有任何其餘影響
package main import "fmt" func main() { x := make(map[string]int) x["A"] = 0 x["B"] = 1 fmt.Println("Before Delete:") fmt.Println("Length:", len(x)) fmt.Println(x) delete(x, "A") fmt.Println("After Delete:") fmt.Println("Length:", len(x)) fmt.Println(x) }
運行結果
6)、map複雜案例一:
package main import "fmt" func main() { var facebook = make(map[string]map[string]int) //注意下面對map賦值,不要對{}回車換行 facebook["2018001"] = map[string]int{"Jemy": 25} facebook["2018002"] = map[string]int{"Andy": 23} facebook["2018003"] = map[string]int{"Bill": 22} for stu_no, stu_info := range facebook { fmt.Println("Student:", stu_no) for name, age := range stu_info { fmt.Println("Name:", name, "Age:", age) } fmt.Println() } }
輸出結果
map複雜案例二(執行結果和上面同樣)
package main import "fmt" func main() { var facebook = map[string]map[string]int{ "2018001": {"Jemy": 25}, "2018002": {"Andy": 23}, "2018003": {"Bill": 22}, } for stu_no, stu_info := range facebook { fmt.Println("Student:", stu_no) for name, age := range stu_info { fmt.Println("Name:", name, "Age:", age) } fmt.Println() } }