#include <stdio.h>ios
int main(){c++
const int constant = 21;
const int* const_p = &constant;
int* modifier = (int*)(const_p);spa
*modifier=10;
printf("%d \n",constant);
return 0;
}io
結果是10stream
#include <iostream>
using namespace std;
int main(){di
const int constant = 21;
const int* const_p = &constant;
int* modifier = (int*)(const_p);ant
*modifier=10;
cout<<constant<<endl;
return 0;
}co
結果是21,這種模擬,對c++屬於未定義操做~return