hdu1018 Big Number

思路：設x是a的位數，則x=log10(a) + 1；ios             因而，結果就是log10(t!)+1=log10(t) + log10(t-1) + ... + log10(2) + 1spa #include <iostream> #include <cmath> using namespace std; int main() { int n; cin>>n

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