題目操蛋就操蛋在給出的int範圍內的數可能會使得數組開不夠,因此用map可能好一點ios
#include <iostream> #include <map> using namespace std; int main() { int n, a, num = 0; cin >> n; map<int, int> m; for (int i = 0; i < n; i++) { cin >> a; m[a]++; } while(++num) if (m[num] == 0) break; cout << num; return 0; }