std::priority_queue
場景:ios
1. 對於一個任務隊列,任務的優先級由任務的priority屬性指明,這時候就須要優先級越高的先執行。而queue並無排序功能,這時priority_queue是比較好的選擇.異步
2 對於異步的task也是同樣,在不斷添加新的task時,固然但願優先級越高的先執行.ide
解析:this
1. 若是須要把優先級最高的先pop,那麼comp比較時須要返回false.spa
代碼:.net
//1.Elements are popped from the "back" of the specific container,
//which is known as the top of the priority queue.
//2.shall return true if a is considered to go before b
// in the strict weak ordering the function defines
#include <stdlib.h>
#include <iostream>
#include <queue>
#include <vector>
using namespace std;
class Task
{
public:
Task(int priority):priority_(priority)
{
}
~Task(){}
int priority_;
void DoWork()
{
cout << "DoWork: " << (int)this << " priority: " << priority_ << endl;
}
};
class PriorityCompare
{
public:
bool operator()(Task* t1,Task* t2)
{
return t1->priority_ > t2->priority_;
}
/* data */
};
int main(int argc, char const *argv[])
{
PriorityCompare pc;
priority_queue<Task*,std::vector<Task*>,PriorityCompare> tasks(pc);
Task t1(1);
Task t2(10);
Task t3(3);
Task t4(1);
Task t5(8);
Task t6(9);
tasks.push(&t1);
tasks.push(&t2);
tasks.push(&t3);
tasks.push(&t4);
tasks.push(&t5);
tasks.push(&t6);
while(!tasks.empty())
{
Task* task = tasks.top();
tasks.pop();
task->DoWork();
}
return 0;
}
blog
輸出:排序
DoWork: 2293456 priority: 1
DoWork: 2293444 priority: 1
DoWork: 2293448 priority: 3
DoWork: 2293440 priority: 8
DoWork: 2293436 priority: 9
DoWork: 2293452 priority: 10隊列
參考: http://www.cplusplus.com/reference/queue/priority_queue/
---------------------
做者:infoworld
來源:CSDN
原文:https://blog.csdn.net/infoworld/article/details/24941961
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