[LeetCode]11.Container With Most Water

Given n non-negative integers a1, a2, ..., an , where each represents
a point at coordinate (i, ai). n vertical lines are drawn such that
the two endpoints of line i is at (i, ai) and (i, 0). Find two lines,
which together with x-axis forms a container, such that the container
contains the most water.

Note: You may not slant the container and n is at least 2.

The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7].
In this case, the max area of water (blue section) the container can
contain is 49.

Example:

Input: [1,8,6,2,5,4,8,3,7] Output: 49
開始把這題想複雜了，決定最大值的只有兩側的高度，遍歷的話o(n^2)的複雜度
不少狀態是重複的
能夠經過雙指針轉化爲貪心問題
對於
100001
目前的狀態下移動擋板只有移動矮的擋板才能可能比當前回大
public int maxArea(int[] height) {

int max=0;
    int l=0;
    int r=height.length-1;
    while(l<r){
        max=Math.max(max,Math.min(height[l],height[r])*(r-l));
        if(height[l]<height[r]) l++;
        else r--;
    }
    return max;

}