1、排名html
/*普通排名:從1開始,順序往下排*/ SELECT cs.*,@r :=@r + 1 AS rank FROM cs,(SELECT @r := 0) r ORDER BY score;
/*並列排名:相同的值是相同的排名*/ SELECT cs.* , CASE WHEN @p=score THEN @r WHEN @p:=score THEN @r:=@r+1 END rank FROM cs,(SELECT @r:=0,@p:=NULL)r ORDER BY score;
/*並列排名:相同的值名次相同,與上例中的並列排名不一樣*/ SELECT city,score,rank FROM ( SELECT cs.*, @c:=IF(@p=score,@c,@r) AS rank, @p:=score, @r:=@r+1 FROM cs ,(SELECT @p:=NULL,@r:=1,@c:=0)r ORDER BY score )c
2、分組後組內排名spa
/*分組普通排名:順序排名*/ SELECT city,score,rank FROM ( SELECT cs.*,IF(@p=city,@r:=@r+1,@r:=1) AS rank,@p:=city FROM cs,(SELECT @p:=NULL,@r:=0)r ORDER BY city,score )s;
/* 分組後並列排名:組內相同數值排名相同*/ SELECT city,score,rank FROM ( SELECT *, IF(@p=city, CASE WHEN @s=score THEN @r WHEN @s:=score THEN @r:=@r+1 END, @r:=1 ) AS rank, @p:=city, @s:=score FROM cs,(SELECT @p:=NULL,@s:=NULL,@r:=0)r ORDER BY city,score )s;
3、分組後取各組的前兩名3d
/*取每組分數高的前兩個,法一*/ SELECT city,score,rank FROM ( SELECT *, IF(@p=city, CASE WHEN @s=score THEN @r WHEN @s:=score THEN @r:=@r+1 END, @r:=1 ) AS rank, @p:=city, @s:=score FROM cs,(SELECT @p:=NULL,@s:=NULL,@r:=0)r ORDER BY city,score DESC )s WHERE rank <3;
/*分組後取前兩個,法二*/ SELECT * FROM cs c WHERE ( SELECT count(*) FROM cs WHERE city=c.city AND score>c.score )<2 ORDER BY city,score DESC
參考:htm
https://www.jianshu.com/p/bb1b72a1623eblog
http://blog.sina.com.cn/s/blog_4c197d420101e408.htmlci