多態性可分爲兩類:靜態多態和動態多態。函數重載和運算符重載實現的多態屬於靜態多態,動態多態性是經過虛函數實現的。ios
每一個含有虛函數的類有一張虛函數表(vtbl),表中每一項是一個虛函數的地址, 也就是說,虛函數表的每一項是一個虛函數的指針。windows
沒有虛函數的C++類,是不會有虛函數表的。函數
兩張圖:性能
簡單例子:spa
1 #include <iostream> 2 #include <windows.h> 3 4 using namespace std; 5 6 class base 7 { 8 virtual void f(){cout<<"base::f"<<endl;}; 9 virtual void g(){cout<<"base::g"<<endl;}; 10 virtual void h(){cout<<"base::h"<<endl;}; 11 }; 12 13 typedef void (*pfun)(); 14 15 void main() 16 { 17 DWORD w=0x4011e0; //虛函數表第一項的內容,也就是第一個虛函數的地址 18 19 pfun fun=NULL; 20 base b; 21 base *pbase=&b; 22 23 fun=(pfun)w; 24 fun(); //調用第一個虛函數 25 }
查看對象b在內存中:指針
查看虛函數表:code
虛函數表的指針4個字節大小(vptr),存在於對象實例中最前面的位置(這是爲了保證取到虛函數表的有最高的性能——若是有多層繼承或是多重繼承的狀況下)。這意味着咱們經過對象實例的地址獲得這張虛函數表,而後就能夠遍歷其中函數指針,並調用相應的函數。對象
虛函數表的結束標誌在不一樣的編譯器下是不一樣的。在VC6.0下,這個值是NULL,如圖:blog
另外一個例子:繼承
1 #include <iostream> 2 3 using namespace std; 4 5 class base 6 { 7 virtual void f(){cout<<"base::f"<<endl;}; 8 virtual void g(){cout<<"base::g"<<endl;}; 9 virtual void h(){cout<<"base::h"<<endl;}; 10 }; 11 12 class Derive : public base 13 { 14 15 public: 16 Derive(){}; 17 virtual void f() { cout << "Derive::f" << endl; } 18 virtual void g() { cout << "Derive::g" << endl; } 19 20 }; 21 22 typedef void(*pfun)(); 23 24 void main() 25 { 26 pfun fun=NULL; 27 Derive d; 28 base *p=&d; 29 30 fun=(pfun)**((int**)p); 31 fun(); //調用第一個虛函數 32 33 fun=(pfun)*(*((int**)p)+2); 34 fun(); //調用第三個函數 35 36 }
查看對象d在內存中:
多重繼承:
有幾個父類,就有幾個vtab和vptr
代碼:
1 #include <iostream> 2 3 using namespace std; 4 5 class Base1 { 6 7 public: 8 9 virtual void f() { cout << "Base1::f" << endl; } 10 11 virtual void g() { cout << "Base1::g" << endl; } 12 13 virtual void h() { cout << "Base1::h" << endl; } 14 15 16 17 }; 18 19 class Base2 { 20 21 public: 22 23 virtual void f() { cout << "Base2::f" << endl; } 24 25 virtual void g() { cout << "Base2::g" << endl; } 26 27 virtual void h() { cout << "Base2::h" << endl; } 28 29 }; 30 31 32 class Base3 { 33 34 public: 35 36 virtual void f() { cout << "Base3::f" << endl; } 37 38 virtual void g() { cout << "Base3::g" << endl; } 39 40 virtual void h() { cout << "Base3::h" << endl; } 41 42 }; 43 44 45 class Derive : public Base1, public Base2, public Base3 { 46 47 public: 48 49 virtual void f() { cout << "Derive::f" << endl; } 50 51 virtual void g1() { cout << "Derive::g1" << endl; } 52 53 }; 54 55 56 typedef void(*Fun)(void); 57 58 int main() 59 60 { 61 62 Fun pFun = NULL; 63 64 Derive d; 65 66 int** pVtab = (int**)&d; 67 68 //Base1's vtable 69 70 //pFun = (Fun)*((int*)*(int*)((int*)&d+0)+0); 71 72 pFun = (Fun)pVtab[0][0]; 73 74 pFun(); 75 76 77 //pFun = (Fun)*((int*)*(int*)((int*)&d+0)+1); 78 79 pFun = (Fun)pVtab[0][1]; 80 81 pFun(); 82 83 84 //pFun = (Fun)*((int*)*(int*)((int*)&d+0)+2); 85 86 pFun = (Fun)pVtab[0][2]; 87 88 pFun(); 89 90 91 //Derive's vtable 92 93 //pFun = (Fun)*((int*)*(int*)((int*)&d+0)+3); 94 95 pFun = (Fun)pVtab[0][3]; 96 97 pFun(); 98 99 100 //The tail of the vtable 101 102 pFun = (Fun)pVtab[0][4]; 103 104 cout<<pFun<<endl; 105 106 107 //Base2's vtable 108 109 //pFun = (Fun)*((int*)*(int*)((int*)&d+1)+0); 110 111 pFun = (Fun)pVtab[1][0]; 112 113 pFun(); 114 115 116 //pFun = (Fun)*((int*)*(int*)((int*)&d+1)+1); 117 118 pFun = (Fun)pVtab[1][1]; 119 120 pFun(); 121 122 123 pFun = (Fun)pVtab[1][2]; 124 125 pFun(); 126 127 128 //The tail of the vtable 129 130 pFun = (Fun)pVtab[1][3]; 131 132 cout<<pFun<<endl; 133 134 135 //Base3's vtable 136 137 //pFun = (Fun)*((int*)*(int*)((int*)&d+1)+0); 138 139 pFun = (Fun)pVtab[2][0]; 140 141 pFun(); 142 143 144 //pFun = (Fun)*((int*)*(int*)((int*)&d+1)+1); 145 146 pFun = (Fun)pVtab[2][1]; 147 148 pFun(); 149 150 151 pFun = (Fun)pVtab[2][2]; 152 153 pFun(); 154 155 156 //The tail of the vtable 157 158 pFun = (Fun)pVtab[2][3]; 159 160 cout<<pFun<<endl; 161 162 163 cout<<sizeof(d)<<endl; 164 165 return 0; 166 167 }