Java中靜態數據的初始化順序

Java的類中的數據成員中包含有靜態成員（static）時，靜態數據成員的初始化順序是怎樣的呢？

【程序實例1】

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */

class Bowl {
    Bowl(int marker) {
        System.out.println("Bowl("+marker+")");
    }
    void f1(int marker) {
        System.out.println("f1("+marker+")");
    }
}

class Table {
    static Bowl bowl1=new Bowl(1);
    Table() {
        System.out.println("Table()");
        bowl2.f1(1);
    }
    void f2(int marker){
        System.out.println("f2("+marker+")");
    }
    static Bowl bowl2=new Bowl(2);
}

class Cupboard {
    Bowl bowl3=new Bowl(3);
    static Bowl bowl4=new Bowl(4);
    Cupboard() {
        System.out.println("Cupboard()");
        bowl4.f1(2);
    }
    void f3(int marker) {
        System.out.println("f3("+marker+")");
    }
    static Bowl bowl5=new Bowl(5);
}

class Ideone
{
    public static void main (String[] args) //throws java.lang.Exception
    {
        System.out.println("Creating new Cupboard() in main");
        new Cupboard();
        System.out.println("Creating new Cupboard() in main");
        new Cupboard();
        table.f2(1);
        cupboard.f3(1);
    }
    
    static Table table=new Table();
    static Cupboard cupboard=new Cupboard();
}

【運行結果】

Bowl(1)
Bowl(2)
Table()
f1(1)
Bowl(4)
Bowl(5)
Bowl(3)
Cupboard()
f1(2)
Creating new Cupboard() in main
Bowl(3)
Cupboard()
f1(2)
Creating new Cupboard() in main
Bowl(3)
Cupboard()
f1(2)
f2(1)
f3(1)

 從上面的執行結果能夠看出：

　　在初始化變量時，Java中static數據成員初始化優先於局部變量，先按定義的順序初始化靜態變量，而後是局部變量，最後執行類的構造函數。