Caculation of Combinations(計算組合數C(m,n))

1、question: C(m,n)=? 2、code:             #include<iostream> #include<cstdio> using namespace std; int fac(int x) { int y=1; for(int i=1;i<=x;i++) y=y*i; return y; } int m,n,ans; int main() { scanf("%d

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